(a) The "average value" of a function over an interval [a,b] is defined to be
(1/(b-a)) times the integral of f from the limits x= a to x = b.
Now S = 200(5 - 9/(2+t))
The average value of S during the first year (from t = 0 months to t = 12 months) is then:
(1/12) times the integral of 200(5 - 9/(2+t)) from t = 0 to t = 12
or 200/12 times the integral of (5 - 9/(2+t)) from t= 0 to t = 12
This equals 200/12 * (5t -9ln(2+t))
Evaluating this with the limits t= 0 to t = 12 gives:
708.113 units., which is the average value of S(t) during the first year.
(b). We need to find S'(t), and then equate this with the average value.
Now S'(t) = 1800/(t+2)^2
So you're left with solving 1800/(t+2)^2 = 708.113
<span>I'll leave that to you</span>
Answer:
0.7429
Step-by-step explanation:
Given that Of the 721 students at the college, 299 of them apply for loans when entering graduate school.
So p = proportion of students applying for loans = 
Each student is independent of the other and there are two outcomes
Hence out of 45 students the no of students who apply for loans say X is binomial with n =45 and p = 0.415
the probability that more than 16 of them apply for loans
=
=0.7429
Answer:
160
Step-by-step explanation:
Plug in 6 for r, and 8 for s in the expression:
(r)(s) + (14)(s) = (6)(8) + (14)(8)
Remember to follow PEMDAS. First, multiply, then add:
(6 * 8) + (14 * 8)
48 + 112
112 + 48 = 160
160 is your answer.
~
Answer:
Step-by-step explanation:
1. y=2x-3
2. y=2x+3
3. y=-2x+3
4. y=-2x-3
A.) 14/15 B.) 17/14 C.) 5/12
