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LenKa [72]
3 years ago
5

A box of mass m is pushed at an angle 0 by a force Fp along a frictionless surface. The box travels to right with acceleration a

. What is the mass of the box?

Physics
2 answers:
Alex787 [66]3 years ago
7 0

Answer:

m = FpCos0 / a

Explanation:

it just is

Genrish500 [490]3 years ago
5 0

Answer:A block rests on a horizontal, frictionless surface. A string is attached to the block, and is pulled with a force of 45.0 N at an…

Explanation:

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In 1865, Jules Verne proposed sending men to the Moon by firing a space capsule from a 220-m-long cannon with final speed of 10.
Sidana [21]

Answer:

The unrealistically large acceleration experienced by the space travelers during their launch is 2.7 x 10⁵ m/s².

How many times stronger than gravity is this force? 2.79 x 10⁴ g.

Explanation:

given information:

s = 220 m

final speed, vf = 10.97 km/s = 10970 m/s

g = 9.8 m/s²

he unrealistically large acceleration experienced by the space travelers during their launch

vf² = v₀²+2as, v₀ = 0

vf² = 2as

a =vf²/2s

  = (10970)²/(2x220)

  = 2.7 x 10⁵ m/s²

Compare your answer with the free-fall acceleration

a/g = 2.7 x 10⁵/9.8

a/g = 2.79 x 10⁴

a = 2.79 x 10⁴ g

7 0
3 years ago
Monochromatic light of wavelength, lambda, is traveling in air. The light then strikes a thin film having an index of refraction
kumpel [21]

Answer:

The  correct option is  H

Explanation:

From the question we are told that

    The index of refraction of  coating is  n_1

       The  index of refraction of material  is  n_2

   

Generally the condition for constructive for a thin film interference is mathematically represented

            2 *  t  = [ m  + \frac{1}{2}] \frac{\lambda}{n_1 }

Here  t represents the thickness

For minimum thickness  m =  0

So

           2 *  t  =0  + \frac{1}{2}\frac{\lambda}{n_1 }

=>        t  =\frac{\lambda}{4n_1 }

3 0
3 years ago
A crane is used to lower weights into a lake for an underwater construction project. Determine the tension in the cable of the c
atroni [7]

Answer:

Tension in the cable = 591292.8 N or 591.3 kN

Explanation:

Tension in the cable = Weight of object in air - upthrust/bouyancy due to the liquid

Weight of object in air = mass * acceleration due to gravity, g

Since mass is not given, it is obtained from the formula, mass = density * volume

Volume of the sphere = 4/3πr³ where r, radius = 2 m; π = 22/7

volume = 4/3 * 22/7 * (2m)³

volume of sphere = 33.52 m³

Density of concrete sphere = specific gravity * density of water

where, specific gravity = 2.8, density of water = 1000 kg/m³

density of concrete =  2.8 * 1000 kg/m³

density of concrete = 2800 kg/m³

acceleration due to gravity, g = 9.8 m/s²

Thus, weight of concrete = 2800 kg/m³ * 33.52 m³ * 9.8 m/s² = 919788.8 N

Upthrust = density of water * volume of sphere * g

Upthrust = 1000 kg/m³ * 33.52 m³ * 9.8 m/s² = 328496 N

The tension in the cable is the calculated as below;

Tension in the cable = Weight of object in air - upthrust/bouyancy due to the liquid

Tension in cable = 919788.8 N - 328.496 N = 591292.8 N

Therefore, tension in the cable is 591292.8 N or 591.3 kN

5 0
3 years ago
What must be the units for the gravitational constant G in order for gravitational force to have units of newtons?
babunello [35]

Answer:

m³/(kg⋅s²)

Explanation:

Hello.

In this case, since the involved formula is:

F=G*\frac{m_1m_2}{r^2}

By writing a dimensional analysis with the proper algebra handling, we obtain:

N[=]G*\frac{kg*kg}{m^2}\\ \\kg*\frac{m}{s^2}[=]G *\frac{kg*kg}{m^2}\\\\G[=]\frac{kg*m*m^2}{kg^2*s^2}\\ \\G[=]\frac{m^3}{kg*s^2}

Thus, answer is:

m³/(kg⋅s²)

Note that the [=] is used to indicate the units of G.

Best regards

4 0
3 years ago
Which object is I’m equilibrium?
IrinaK [193]

Equilibrium is a state of no motion. If donuts are on the table, they are in equilibrium. Literally anything that is NOT moving relative to the earth is in equilibrium. The chair is in equilibrium, the table is in equilibrium, the cookies are in equilibrium, and so on.

3 0
3 years ago
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