Answer:
it burns things which would be burned easily by lightning, and then people put the fire out immediately. If the dried plants that they are lighting on fire are hit by lightning, it can lead to a massive fire without anyone realizing.
C6H12O6 + 6 O2 --> 6 CO2 + 6 H2O
Answer:
To release 7563 kJ of heat, we need to burn 163.17 grams of propane
Explanation:
<u>Step 1</u>: Data given
C3H8 + 5O2 -----------> 3CO2 + 4H2O ΔH° = –2044 kJ
This means every mole C3H8
Every mole of C3H8 produces 2044 kJ of heat when it burns (ΔH° is negative because it's an exothermic reaction)
<u>Step 2: </u>Calculate the number of moles to produce 7563 kJ of heat
1 mol = 2044 kJ
x mol = 7563 kJ
x = 7563/2044 = 3.70 moles
To produce 7563 kJ of heat we have to burn 3.70 moles of C3H8
<u>Step 3: </u>Calculate mass of propane
Mass propane = moles * Molar mass
Mass propane = 3.70 moles * 44.1 g/mol
Mass propane = 163.17 grams
To release 7563 kJ of heat, we need to burn 163.17 grams of propane
Answer:
a. The second run will be faster.
d. The second run has twice the surface area.
Explanation:
The rate of a reaction is proportional to the surface area of a catalyst. Given the volume (V) of a sphere, we can find its surface area (A) using the following expression.
![A=\pi ^{1/3} (6V)^{2/3}](https://tex.z-dn.net/?f=A%3D%5Cpi%20%5E%7B1%2F3%7D%20%286V%29%5E%7B2%2F3%7D)
The area of the 10.0 cm³-sphere is:
![A=\pi ^{1/3} (6.10.0)^{2/3}=22.4cm^{2}](https://tex.z-dn.net/?f=A%3D%5Cpi%20%5E%7B1%2F3%7D%20%286.10.0%29%5E%7B2%2F3%7D%3D22.4cm%5E%7B2%7D)
The area of each 1.25 cm³-sphere is:
![A=\pi ^{1/3} (6. 1.25)^{2/3}=5.61cm^{2}](https://tex.z-dn.net/?f=A%3D%5Cpi%20%5E%7B1%2F3%7D%20%286.%201.25%29%5E%7B2%2F3%7D%3D5.61cm%5E%7B2%7D)
The total area of the 8 1.25cm³-spheres is 8 × 5.61 cm² = 44.9 cm²
The ratio of 8 1.25cm³-sphere to 10.0 cm³-sphere is 44.9 cm²/22.4 cm² = 2.00
Since the surface area is doubled, the second run will be faster.