Ask question

Ask question

All categories

3 years ago

8

Why did corn borers increase after the fields were sprayed for beetles?

2 answers:

Vera_Pavlovna [14]3 years ago

5 0

Answer:

The natural predators for the borers was gone

mina [271]3 years ago

4 0

<span>After the fields were sprayed for beetles corn borers increased because their natural predator was gone. The beetles had been keeping the corn borers at bay but once their natural predator had been eradicated the corn borers were protected and flourished.</span>

You might be interested in

One car has two and a half times the mass of a second car, but only half as much kinetic energy. When both cars increase their s

Leokris [45]

Answer:

$v_1 = 7.96 m/s$

$v_2 = 17.8 m/s$

Explanation:

Let the mass of the other car is "m" and its kinetic energy is

$K = \frac{1}{2}mv^2$

now the mass of the first car is two and half times and its kinetic energy is half that of other car

so we will have

$\frac{1}{2}(2.5m)v_1^2 = \frac{1}{2}(\frac{1}{2}mv^2)$

$2.5 v_1^2 = 0.5 v^2$

$v_1 = 0.447 v$

now speed of both cars is increased by value of 9 m/s

so now we will have same kinetic energy for both cars

$\frac{1}{2}(2.5 m)(0.447v + 9)^2 = \frac{1}{2}m(v + 9)^2$

$2.5(0.447 v + 9)^2 = (v + 9)^2$

$1.58(0.447v + 9) = v + 9$

$0.293v = 5.22$

$v = 17.8 m/s$

so speed of first car is

$v_1 = 0.447 v = 7.96 m/s$

$v_2 = 17.8 m/s$

3 0

3 years ago

A bowling ball of 35.2 kg, generates 218 kg* m/s units of momentum. What is the velocity of the ball?

Aleonysh [2.5K]

Answer:

6.19 m/s

Explanation:

$p = mv \\ 218 = (35.2)(v ) \\ v = 6.19 \: ms {}^{ - 1}$

7 0

3 years ago

Alkali metals _____.

Lyrx [107]

I think the answer is C

7 0

3 years ago

Two cars are driving on a straight section of the interstate in opposite directions with 70 mph. They are one mile apart.

Mashutka [201]

They are trailing the same speed as it states in the question they are heeding toward each other a 70 mph <span />

5 0

3 years ago

A set of four capacitors are attached to a 12V battery in the circuit shown below. All capacitances are measured in milli-Farads

Bond [772]

The amount of electric charge that resides on each capacitor once it is fully charged is 0.37 C.

<h3>Total capacitance of the circuit</h3>

The total capacitance of the circuit is calculated as follows;

Capacitors in series;

1/Ct = 1/8 + 1/7.5

1/Ct = 0.25833

Ct = 3.87 mF

Capacitors is parallel;

Ct = 3.87 mF + 12 mF + 15 mF

Ct = 30.87 mF

Ct = 0.03087 F

<h3>Charge in each capacitor</h3>

Q = CV

Q = 0.03087 x 12

Q = 0.37 C

Thus, the amount of electric charge that resides on each capacitor once it is fully charged is 0.37 C.

Learn more about capacitors here: brainly.com/question/13578522

#SPJ1

3 0

2 years ago