How is it that substances can have the same chemical formulas but make different types of matter?

Robin Hood wishes to split an arrow already in the bull's-eye of a target 40 m away.

tamaranim1 [39]

Answer:

5.843 m

Explanation:

suppose that the arrow leave the bow with a horizontal speed , towards he bull's eye.

lets consider that horizontal motion

distance = speed * time

time = 40/ 37 = 1.081 s

arrow doesnot have a initial vertical velocity component. but it has a vertical motion due to gravity , which may cause a miss of the target.

applying motion equation

(assume g = 10 m/s²)

$s=ut+\frac{1}{2}*gt^{2} \\= 0+\frac{1}{2}*10*1.081^{2}\\= 5.843 m$

Arrow misses the target by 5.843m ig the arrow us split horizontally

4 0

3 years ago

a boy looks at the reflection of his digital watch in a plane mirror and thinks the time is 10:11. what is the correct time?

Gekata [30.6K]

Answer:

11:10 will be the time. reflection causes the object to be flipped when you see its image at the mirror

6 0

3 years ago

How long does it take the sun to melt a block of ice at 0âc with a flat horizontal area 1.0 m2 and thickness 1.8 cm ? assume tha

snow_lady [41]

At least 20-30 seconds

3 0

4 years ago

A 1-m3 tank containing air @ 25 oC & 500 kPa is connected to another tank containing 5 kg of air at 35 oC & 200 kPa thro

VladimirAG [237]

Answer:

Volume of Tank 2, V' = $2.17 m^{3}$

Equilibrium Pressure, $P_{eq} = 278.82 kPa$

Given:

Volume of Tank 1, V = 1 $m^{3}$

Temperature of Tank 1, T = $25^{\circ}C$ = 298 K

Pressure of Tank 1, P = 500 kPa

Mass of air in Tank 2, m = 5 kg

Temperature of tank 2, T' = $35^{\circ}C$ = 303 K

Pressure of Tank 2, P' = 200 kPa

Equilibrium temperature, $20^{\circ}C$ = 293 K

Solution:

For Tank 1, mass of air in tank can be calculated by:

PV = m'RT

$m' = \frac{PV}{RT}$

$m' = \frac{500\times 1}{0.287\times 298} = 5.85 kg$

Also, from the eqn:

PV' = mRT

V' = volume of Tank 2

Thus

V' = $\frac{mRT}{P}$

V' = $\frac{5\times 0.287\times 303}{200} = 2.17 m^{3}$

Now,

Total Volume, V'' = V + V' = 1 + 2.17 = 3.17 $m^{3}$

Total air mass, m'' = m + m' = 5 + 5.85 = 10.85 kg

Final equilibrium pressure, P'' is given by:

$P_{eq}V'' = m''RT_{eq}$

$P_{eq} = \frac{m''RT_{eq}}{V''}$

$P_{eq} = \frac{10.85\times 0.87\times 293}{3.17} = 287.82 kPa$

$P_{eq} = 287.82 kPa$

3 0

3 years ago

(based on an image by Geek3,Creative Commons license) Which statement best describes charge A and charge B in this diagram

ivanzaharov [21]

As per the properties of field lines we know that

1. Electric field lines originates from positive charge and terminates at negative charge

2. number of field lines originated outwards is directly proportional to the magnitude of charge

So here we can say that number of field lines linked with charge A is more than B so magnitude of charge A will be more

Also we can see that field lines are originated out from charge A and terminated in charge B so charge A is positive and charge B is negative

so the correct answer will be

<u>A). The signs on charges A and B are opposite. The amount of charge on A is greater than that on B.</u>

5 0

3 years ago