1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
a_sh-v [17]
3 years ago
12

______ is the best way to determine your own correct intensity level.

Physics
1 answer:
scZoUnD [109]3 years ago
5 0
<span>Self-monitoring would be the best way to </span><span>determine your own correct intensity level. I hope this helps! <3
</span>
You might be interested in
A car travels at the speed of 117km/h.How far will the car travels in 50 minutes​
lorasvet [3.4K]

Answer:

117/60*50

Explanation:

Trust me bc I'm smart

8 0
3 years ago
Read 2 more answers
Define in your own words solubility
Andrews [41]
If something is water-soluble, then that means the substance can be dissolved in water. 

So... (water) solubility would be the quality of a substance that allows it to be dissolved in water

I hope this helped! If you have any other questions, just ask, and I hope you have a great day! :)


3 0
3 years ago
Read 2 more answers
Imagine that I have a ping-pong ball and a bowling ball resting on the floor of our classroom. I go up to the bowling ball and g
MatroZZZ [7]

Answer:

the speed and aceleration of the ping pong ball is greater than that of the bowling ball.

Explanation:

We can analyze this exercise from several points of view, if we use Newton's second law

Bowling ball

           F = M a₁

pingpongg ball

           F = m a₂

as the forces the same

          M a₁ = m a₂

          a₂ = \frac{M}{m} a₁

Since the mass of the bowling ball is much greater than the ping pong ball,

          a₂ »a₁

so the acceleration of the ping pong ball is much greater than the acceleration of the bowling ball.

If we use the relationship of momentum and momentum, assuming that the time for the two cases is the same and that both start from rest

Bowling ball

           I = F t = Δp

           I = M (v₁ - v₀)

Ping pong ball

           I = F t = Δp

           I = m (v₂ -v₀)

the impulse itself

          M v₁ = m v₂

          v₂ = \frac{M }{ m} v₁

so we conclude that the speed of the ping pong ball is much greater than the speed of the bowling ball.

In conclusion the speed and aceleration of the ping pong ball is greater than that of the bowling ball.

4 0
3 years ago
two identical 1.00 x 10^-4 C charges have an electric potential energy of 100 J. how far apart are they. (Unit = m)
STALIN [3.7K]

Answer: 0.899

Explanation:

acellus

8 0
3 years ago
Read 2 more answers
The cross sectional area of an optical fibre is 6.3 x 10^-6 m^2 The intensity of the light entering the optical fibre is 3.2 x 1
gogolik [260]

the answer is 0.0. also known as a emoji face!

7 0
3 years ago
Other questions:
  • What is the potential energy of a 25 kg bicycle resting at the top of a hill 3 m high? (Formula: PE = mgh)
    5·2 answers
  • the momentum of a moving car can be calculated by multiplying the car's mass by the cars velocity. Which of the following quanti
    15·1 answer
  • Can someone help me with this question?¿
    12·1 answer
  • An example of a single displacement reaction is
    11·2 answers
  • A bike travels 35A bike travels 35.896 meters in 6.25 seconds. The average speed is then calculated.
    10·2 answers
  • Two car horns are sounded creating two sound waves with frequencies that differ by a factor of three. How does the speed of the
    10·1 answer
  • Describe the story of the constellation Capricornus. WILL MARK BRAINLEST IF NOT STOLEN FROM A WEBSITE OR ANYTHING WITH A PROPER
    9·2 answers
  • The skateboarder in the drawing starts down the left side of the ramp with an initial speed of 6.4 m/s. Neglect nonconservative
    6·1 answer
  • Explain how the fountain pen is filled up with ink​
    13·1 answer
  • Difference between <br>Plz help me <br>Plzz ​
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!