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miskamm [114]
3 years ago
15

The relative angle at the knee changes from 0 to 85 degrees during the knee flexion phase of a squat exercise. If 10 complete sq

uats are performed, what is the total angular distance undergone at the knee (in degrees)?
Physics
1 answer:
strojnjashka [21]3 years ago
6 0

Answer: the total angular distance undergone at the knee is 1700°

Explanation:

You know that in a knee flexion, the angle goes from 0° to 85.

Now, in one squat, the knee flex and the angle goes from 0° to 85° (85° of angular distance) and when the knee straigthens, the angle goes from 85° to 0° (another 85° of angular distance)

So in one squat, the total angular distance undergone at the knee is d = 85° + 85° = 170°

and if in one squat, the angular distance is 170°, in ten, the angular distance will be ten times that number:

d = 10*170° = 1700°

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Answer:

684.5 is the weight on mars and 1813 on earth

Explanation:

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6 0
3 years ago
When is the pressure of the man on the ground more – lying position or standing
Wittaler [7]

Hi,

<u>The man on the ground in standing position has more pressure</u>. This is because when he stands, only his legs are in contact with the ground. While lying, his body is more in contact with the ground, therefore, he exerts less pressure.

To the point, a man standing position on the ground had more pressure.

More is the area of contact, less is the pressure efforted.

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3 years ago
__________ is when a person becomes less sensitive to a drug. A. Tolerance B. Craving C. Addiction D. Dependence
Luden [163]
A) Tolerance

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4 0
3 years ago
An electric wall clock has a second hand 15 cm long. at the tip of his hand, what is the magnitude of the velocity?
Mila [183]

The velocity of the tip of the second hand is 0.0158 m/s

Explanation:

First of all, we need to calculate the angular velocity of the second hand.

We know that the second hand completes one full circle in

T = 60 seconds

Therefore, its angular velocity is:

\omega = \frac{2\pi}{T}=\frac{2\pi}{(60)}=0.105 rad/s

Now we can calculate the velocity of a point on the tip of the hand by using the formula

v=\omega r

where

\omega=0.105 rad/s is the angular velocity

r = 15 cm = 0.15 m is the radius of the circle (the distance of the point from the centre of rotation)

Substituting,

v=(0.105)(0.15)=0.0158 m/s

Learn more about angular motion here:

brainly.com/question/9575487

brainly.com/question/9329700

brainly.com/question/2506028

#LearnwithBrainly

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3 years ago
A blue train of mass 50 kg moves at 4 m/s toward a green train of 30 kg initially at rest. The trains collide. After the collisi
ra1l [238]

Explanation:

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p = (30 kg) (3 m/s)

p = 90 kg m/s

7 0
3 years ago
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