Question

For the following reaction, what volume of NOBr can be produced from 3.8 L of Br2 (measured at the same temperature and pressure), assuming an excess of NO?
2NO(g)+Br2(g)=2NO(Br)2

Answer 1

Boi if you don’t get ya thing out of here with that who the hell knows that

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Answer 2

Answer:

$7.6LNOBr$

Explanation:

Hello,

In this case, since no temperature and pressure are known, one could develop the stoichiometric relationship for 1 mole of $Br_2$ per 2 moles of $NOBr$ in terms of volume as shown below because of the Avogadro's law (change in mole proportional to the change in volume at constant both pressure and temperature):

$3.8LBr_2*\frac{2LNOBr}{1LBr_2} =7.6LNOBr$

Best regards.