All categories

3 years ago

(6.710^3)g/molL to kg/mol*dL

Chemistry

2 answers:

Nastasia [14]3 years ago

8 0

Answer : The answer is, $0.67\text{ Kg}/mole\text{ dL}$

Step by step explanation :

For this problem the conversion factors used are,

$(1kg=1000g)\\\\(1L=10dL)$

Convert $6.7\times 10^3\text{ g}/mole\text{ L}$ to $\text{ Kg}/mole\text{ dL}$ :

$6.7\times 10^3\text{ g}/mole\text{ L}\\\\\Rightarrow \frac{6.7\times 10^3}{10^3}\text{ Kg}/mole\text{ L}\\\\\Rightarrow \frac{6.7}{10}\text{ Kg}/mole\text{ dL}\\\\\Rightarrow 0.67\text{ Kg}/mole\text{ dL}$

Hence, the answer is, $0.67\text{ Kg}/mole\text{ dL}$

vodka [1.7K]3 years ago

7 0

6.7× 10³ g/mol*L ×(1Kg÷1000g) × (1L÷10dL)= 0.67

You might be interested in

A pair of students found the temperature of 100. g of water to be 26.5°C. They then dissolved 8.89 g of AgNO3 in the water. When

bekas [8.4K]

Explanation:

Initial temperature of the water = $T_i=26.5^oC$

Final temperature of the water = $T_f=23.7^oC$

a) Change in temperature of the water,ΔT = $T_f-T_i$

$\Delta T=23.7^oC-26.5^oC=-2.8^oC$

Change in temperature of the water,ΔT is -2.8°°C.

b) Endothermic reaction : Reaction in which heat absorbed and the temperature if the surrounding is decreased.

Exothermic reaction : Reaction in which heat released and the temperature if the surrounding is increased.

On dissolving silver nitrate in water the temperature of the water decreased 2.8 degree Celsius which means that energy water was absorbed by solid silver nitrate to get dissolve in water. Hence, endothermic reaction.

(f) Mass of silver nitrate = 8.89 g

Moles of silver nitrate = $\frac{8.89 g}{170 g/mol}=0.05229 mol$

$AgNO_3(aq)\rightarrow Ag^+(aq)+NO_3^-(aq)$

1 mole of silver nitrate gives 1 mole of silver ion i.e. cation.

Then 0.05229 moles of silver nitrate will give:

$\frac{1}{1}\times 0.05229 mol=0.05229 mol$ silver ions.

0.05229 moles of cations are produced.

1 mole of silver nitrate gives 1 mole of nitrate ion i.e. anion .

Then 0.05229 moles of silver nitrate will give:

$\frac{1}{1}\times 0.05229 mol=0.05229 mol$ nitrate ions.

0.05229 moles of anion are produced.

5 0

3 years ago

HELP PLEASE FAST 100 POINTS

gizmo_the_mogwai [7]

In any chemical reaction, the mass of the products must equal the mass of the reactants. The mass of product B is the same as the combined mass of Reactant A and H₂O.

4 0

2 years ago

liquid octane(CH3)(CH2)6CH3) reacts with gaseous oxygen gas(O2) to produce gaseous carbon dioxide(CO2) and gaseous water(H2O). I

max2010maxim [7]

The percent yield of carbon dioxide will be 49.0 %.

<h3>Percent yield</h3>

First, let's look at the equation of the reaction:

$2C_8H_1_8 + 25O_2 -- > 16CO_2 + 18H_2O$

The mole ratio of octane to oxygen is 2:25.

Mole of 3.43 g octane = 3.43/114.23 = 0.03 mol

Mole of 19.1 g oxygen = 19.1/32 = 0.60 mol

Thus, octane is limiting.

Mole ratio of octane to carbon dioxide = 2:16.

Equivalent mole of carbon dioxide = 0.03 x 8 = 0.24 mol

Mass of 0.24 mol carbon dioxide = 0.24 x 44.01 = 10.5624 grams

Percent yield of carbon dioxide = 5.18/10.5624 = 49.0 %

More on percent yield can be found here: brainly.com/question/17042787

#SPJ1

6 0

1 year ago

I need help so please help me

Kay [80]

Answer:b

Explanation:

I honestly don’t know if this I right but that would be my guess

3 0

3 years ago

When considering light moving through a diffraction grating, you should treat the light as what?

liraira [26]

Answer:

A particle

Explanation:

Modern quantum theory holds that light has both wave-like and particle-like properties. When the length scales involved are large compared to the wavelengths of light (ex., forming images with thin lenses), the

particle nature of light dominates.

5 0

3 years ago

Read 2 more answers

(6.7*10^3)g/mol*L to kg/mol*dL

(6.710^3)g/molL to kg/mol*dL