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Ugo [173]
3 years ago
9

In a water molecule, two hydrogen atoms bind to one oxygen atom. How many lone pairs of electrons will be shown around each hydr

ogen atom in the Lewis structure of water?
Chemistry
2 answers:
german3 years ago
6 0
Zero lone pairs of electrons, because the water molecule is a bent shape, meaning that the atom in the center has the lone pairs of electrons which is Oxygen, not Hydrogen. 
anzhelika [568]3 years ago
5 0
There are no lone pair of electrons shown around the hydrogen atoms, rather there are 2 lone election pairs present around the central atom in this Lewis structure and that is Oxygen. Hydrogen only has bonding electrons, and it requires 2 electrons per hydrogen to achieve stability and have a full valence electron shell.
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What mass of solid that has a molar mass of 46.0 g/mol should be added to 150.0 g of benzene to raise the boiling point of benze
enyata [817]

Answer : 17.12 g

Explanation:\Delta T =k_b\times m

\Delta T = elevation in boiling point

k_b = boiling point elevation constant

m= molality

molality=\frac{mass of solute}{molecular mass of solute\times weight of the solvent in kg}

given \Delta T=6.28^{\circ}C

Molar mass of solute = 46.0 gmol^{-1}

Weight of the solvent = 150.0 g = 0.15 kg

Putting in the values

molality=\frac{x}{46gmol^{-1}\times0.15kg}

6.28 =2.53^{\circ}Ckgmol^{-1}\frac{x}{46gmol^{-1}\times 0.15kg}

x = 17.12 g



3 0
3 years ago
How did Democritus contribute to the development of the atom?
matrenka [14]

Democritus developed the atomic model. He theorized that atoms were specific to the material which they composed. He also believed that the atoms different in size and shape, were in constant motion in a void, collided with each other; and during these collisions, could stick together.

6 0
3 years ago
write the balanced equation for the reaction that occurs when butane undergoes combustionWhat is the coefficient of oxygen in th
love history [14]

Answer:

2C4H10 + 13O2 ----> 4CO2 + 10H2O

The coefficient of oxygen in the balanced equation is 13

5 0
3 years ago
What is the molecular formula of a compound containing 89% cesium (Cs) and 11% oxygen (O) with a molar mass = 298 g/mol?
Maurinko [17]
M(Cs)=133 g/mol
M(O)=16 g/mol
M(CsxOy)=298 g/mol
w(Cs)=0.89
w(O)=0.11

CsxOy

x=M(CsxOy)w(Cs)/M(Cs)
x=298*0.89/133=2

y=M(CsxOy)w(O)/M(O)
y=298*0.11/16=2

Cs₂O₂  cesium peroxide
6 0
3 years ago
Read 2 more answers
Calculate the mass of a 0.297-mL sample of a liquid with a density of 0.930 g/mL.
tekilochka [14]

Answer: 0.27621 g

Explanation:

0.297 ml *0.930 g/ml=0.27621 g

8 0
1 year ago
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