Answer:
The correct approach is "12.25°C".
Explanation:
Given:
Mass of lead,
mc = 245 g
Initial temperature,
tc = 300°C
Mass of Aluminum,
ma = 150 g
Initial temperature,
ta = 12.0°C
Mass of water,
mw = 820 g
Initial temperature,
tw = 12.0°C
Now,
The heat received in equivalent to heat given by copper.
The quantity of heat = 
then,
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
<span>Answer:
(0.150 L) x (0.0240 M Fe{3+}) x (3 mol OH{-} / 1 mol Fe{3+}) / (1.39 M NaOH) = 0.00777 L = 7.77 mL NaOH</span>
Answer: ok that was i am doing
Explanation: like help them
Answer:here is the answer
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Explanation: