Answer:
B highlands and polar, very little percipitation is found in polar regions, and high lands contributes to that
Explanation:
Answer:
V₁ = 0.342 M
Explanation:
Given data:
Volume of HClO₄ = 15.00 mL
Volume of NaOH = 25.64 mL
Molarity of NaOH = 0.2000 M
Molarity of HClO₄ = ?
Solution:
Formula:
M₁V₁ = M₂V₂
V₁ = M₂V₂ /M₁
V₁ = 0.2000 M ×25.64 mL /15.00 mL
V₁ = 5.128 M. mL /15.00 mL
V₁ = 0.342 M
The reaction is;
2Na + 2H2O → 2NaOH + H2
Answer:
4.4 × 10^(23) atoms
Explanation:
The reaction is;
2Na + 2H2O → 2NaOH + H2
2 moles of Na produces 1 mole of H2 from the equation reaction.
Thus, since 8.2 L of hydrogen gas at STP are produced. And we know that at STP, 1 mole of a gas will have a volume of 22.4 L, and also, We know according to avogadro's number that, 1 mol = 6.02 × 10^(23) atoms, Thus;
8.2 L of H2 × (1 mole of H2/22.4 L) × (2 mole of Na/1 mole of H2) × (6.02 × 10^(23) atoms/1 mole of Na) = 4.4 × 10^(23) atoms
Answer:
3 g/mL
Explanation:
We know that the density of an object can be measured by dividing its mass (g) to its volume (mL).
Formula
D=m/v
Given data:
Mass= 45 g
Volume= 15 mL
Now we will put the values in formula:
D=45 g/ 15 mL= 3 g/mL
Answer:
The molar amount of gas.
Explanation:
According to the ideal gas law,
PV = nRT
P = pressure of gas
V = volume of gas
n = number of moles of gas
R = ideal gas constant
T= temperature of gas
When pressure, volume and temperature of gas is known the molar amount of gas can be determine by using above formula.
For example:
P = 1.2 atm
R = 0.0821 atm. L.mol⁻¹ .k⁻¹
T = 293 K
V = 2 L
n = ?
Solution:
PV = nRT
1.2 atm × 2L= n × 0.0821 atm. L.mol⁻¹ .k⁻¹ × 293 K
n = 1.2 atm × 2L / 0.0821 atm. L.mol⁻¹ .k⁻¹ × 293 K
n = 0.1 mol
