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Alex787 [66]
2 years ago
5

What volume of 0.555M KNO3 solution would contain 12.5 g of solute

Chemistry
1 answer:
Lorico [155]2 years ago
3 0

The volume of 0.555M KNO3 solution would contain 12.5 g of solute iss 223 mL.

<h3>What is the relationship between mass of solute and concentration of solution?</h3>

The mass of solute in a given volume of solution is related by the formula below:

  • Molarity = mass/(molar mass * volume)

Therefore, volume of solution is given by:

Volume = Mass /molarity * molar mass

Molar mass of KNO₃ = 101 g/mol

Volume = 12.5/(0.555 * 101)

Volume = 0.223 L or 223 mL

In conclusion, the volume of the solution is obtained from the molarity of solution as well as mass and molar mass of solute.

Learn more about molarity and volume at: brainly.com/question/26873446
#SPJ1

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Answer:

5.702 mol K₂SO₄

General Formulas and Concepts:

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Compounds
  • Moles

<u>Stoichiometry</u>

  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

[Given] 993.6 g K₂SO₄

[Solve] moles K₂SO₄

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of K: 39.10 g/mol

[PT] Molar Mass of S: 32.07 g/mol

[PT] Molar mass of O: 16.00 g/mol

Molar Mass of K₂SO₄: 2(39.10) + 32.07 + 4(16.00) = 174.27 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                       \displaystyle 993.6 \ g \ K_2SO_4(\frac{1 \ mol \ K_2SO_4}{174.27 \ g \ K_2SO_4})
  2. [DA] Divide [Cancel out units]:                                                                         \displaystyle 5.7015 \ mol \ K_2SO_4

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 4 sig figs.</em>

5.7015 mol K₂SO₄ ≈ 5.702 mol K₂SO₄

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