What volume of 0.555M KNO3 solution would contain 12.5 g of solute
1 answer:
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Answer:
0.075 m solution has the lowest freezing point.
Explanation:
Depression in freezing point is given by:
where,
=Depression in freezing point
= Freezing point constant of solvent
1 - van't Hoff factor
m = molality
According question, molality of all the solutions are same and are in prepared with same solvent. So, values of molality and will remain the same and will not effect the freezing point of the solution.
The lowering in freezing point will now depend upon van't Hoff factors of the solutions. Higher the value of van'Hoff factor more will be the lowering in freezing point of the solution.
The van't Hoff factor of solution =
The van't Hoff factor of solution =
The van't Hoff factor of solution =
The van't Hoff factor of solution =
The van't Hoff factor of solution =
The solution of ammonium phosphate has the highest values of van't Hoff factor which will result in maximum lowering of the freezing point of the solution.
Hence, 0.075 m solution has the lowest freezing point.
Answer:
V2 = 9.58 Litres.
Explanation:
Given the following data;
Initial volume = 25 L
Initial pressure = 115 kPa
Final pressure = 300 kPa
To find the new volume V2, we would use Boyles' law.
Boyles states that when the temperature of an ideal gas is kept constant, the pressure of the gas is inversely proportional to the volume occupied by the gas.
Mathematically, Boyles law is given by;
Substituting into the equation, we have;
V2 = 9.58 L
Therefore, the new volume is 9.58 litres.