Now ,
C + O2 → CO2
According to above equation, 1 mole of carbon reacts with one mole of oxygen to produce one mole of carbon dioxide.Thus this implies that 12 g of carbon reacts with 32 g of O2 to produce 44 g of CO2.
No of moles = mass of the substance/molecular mass of the substance.
In this case 1.2 g of carbon reacts with "x "g of O2 to produce 4.4 g of CO2.
No of moles of carbon in this case = 1.2÷ 12 = 0.1 moles.
No of moles of carbon dioxide formed = 4.4÷44 =0.1 moles
Thus already discussed above, 1 mole of carbon reacts with 1 mole of oxygen to produce 1 mole of carbon dioxide. Hence to produce 0.1 mole of CO2 ,0.1 mole of carbon needs to react with 0.1 mole of oxygen.
Also number of moles of O2 = mass of O2÷ molar mass of O2
Substituting number of moles of O2 as 0.1 we get
mass of O2(x) = Number of moles of O2 × Molar mass of O2
Mass of O2 (x) = 0.1 × 32= 3.2 g
Thus mass of 3.2 g O2 reacts with 1.2 g of CO2 to produce 4.4 g of CO2.
Answer:
19.5g is the theoretical yield of alum
Explanation:
Based on the balanced reaction, 4 moles of sulfuric acid produce 2 moles of alum. To solve this question we need to find the moles of H2SO4. With these moles we can find the moles of alum and its mass assuming all sulfuric acid reacts producing alum.
<em>Moles Sulfuric Acid:</em>
8.3mL = 0.0083L * (9.9mol/L) = 0.08217 moles sulfuric acid
<em>Moles Alum:</em>
0.08217 moles sulfuric acid * (2mol KAl(SO4)2•12H2O / 4mol H2SO4) =
0.041085 moles KAl(SO4)2•12H2O
<em>Mass Alum -Molar mass: 474.3884 g/mol-</em>
0.041085 moles KAl(SO4)2•12H2O * (474.3884 g/mol) =
<h3>19.5g is the theoretical yield of alum</h3>
Missing question:
A. All carbon atoms are identical.
B. An oxygen atom combines with 1.5 hydrogen atoms to form a water molecule.
C. Two oxygen atoms combine with a carbon atom to form a carbon dioxide molecule.
D. The formation of a compound often involves the destruction of one or more atoms.
Answer is: B and D.
A is correct because Daltan stated: All atoms of a given element have the same mass and other properties that distinguish them from the atoms of other elements.
C is correct because atoms combine in simple, whole- number ratios to form compounds, B is incorrect because ratio is not simple, whole number.
D is incorrect because according to Dalton. atoms can't be created or destroyed.
Answer:
The ppm carbon in the seawater is 104.01.
Explanation:
Mass of seawater = 6.234 g
Mass of carbon dioxide gas produced = 2.378 mg = 0.002378 g
1 mg = 0.001 g
Moles of carbon dioxide gas = 
1 mol of carbon dioxde gas has 1 mole pf carbon atoms,then 
will have ;
of carbon
Mass of of carbon ;
To calculate the ppm of oxygen in sea water, we use the equation:
(Both the masses are in grams)
The ppm carbon in the seawater is 104.01.
It’s the first one ( plants can grow in between rocks and break them into smaller pieces)
