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butalik [34]
3 years ago
8

Gasoline and motor oil are chemically similar. They are both mixtures of nonpolar hydrocarbons

Chemistry
2 answers:
Lyrx [107]3 years ago
6 0

Answer:

Motor oil

Heat it

Water

Explanation:

Softa [21]3 years ago
5 0

Answer:

motor oil

Explanation:

According to Oxford dictionary, viscosity refers to ''a quantity expressing the magnitude of internal friction in a fluid, as measured by the force per unit area resisting uniform flow.''

The higher the molecular weight of a substance, the greater its viscosity. This is because, the long chains in the viscous substance become entangled thereby increasing the internal friction in the liquid.

Motor oil is a heavier hydrocarbon than gasoline hence it is more viscous than gasoline.

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Calculate the pH of a solution that contains 2.7 M HF and 2.7 M HOC6H5. Also, calculate the concentration of OC6H5- in this solu
borishaifa [10]

Answer:

\large \boxed{\mathbf{1.36; 3.6 \times 10^{\mathbf{-9}}}\textbf{mol/L}}

Explanation:

The HF is about five million times as strong as phenol, so it will be by far the major contributor of hydronium ions. We can ignore the contribution from the phenol.

1 .Calculate the hydronium ion concentration

We can use an ICE table to organize the calculations.

                    HF + H₂O ⇌ H₃O⁺ + F⁻

I/mol·L⁻¹:       2.7                   0       0

C/mol·L⁻¹:      -x                   +x      +x

E/mol·L⁻¹:   2.7 - x                 x        x

K_{\text{a}} = \dfrac{\text{[H}_{3}\text{O}^{+}] \text{F}^{-}]} {\text{[HF]}} = 7.2 \times 10^{-4}\\\\\dfrac{x^{2}}{2.7 - x} = 7.2 \times 10^{-4}\\\\\text{Check for negligibility of }x\\\\\dfrac{2.7}{7.2 \times 10^{-4}} = 4000 > 400\\\\\therefore x \ll 2.7\\\dfrac{x^{2}}{2.7} = 7.2 \times 10^{-4}\\\\x^{2} = 2.7 \times 7.2 \times 10^{-4} = 1.94 \times 10^{-3}\\x = 0.0441\\\text{[H$_{3}$O$^{+}$]}= \text{x mol$\cdot$L$^{-1}$} = \text{0.0441 mol$\cdot$L$^{-1}$}

2. Calculate the pH

\text{pH} = -\log{\rm[H_{3}O^{+}]} = -\log{0.0441} = \large \boxed{\mathbf{1.36}}

3. Calculate [C₆H₅O⁻]

C₆H₅OH + H₂O ⇌ C₆H₅O⁻ + H₃O⁺

     2.7                         x        0.0441

K_{\text{a}} = \dfrac{0.0441x} {2.7} = 1.6 \times 10^{-10}\\\\0.0441x = 1.6 \times 10^{-10}\\x = \dfrac{1.6 \times 10^{-10}}{0.0441} = \mathbf{3.6 \times 10^{\mathbf{-9}}}\textbf{ mol/L}\\\text{The concentration of phenoxide ion is $\large \boxed{\mathbf{3.6 \times 10^{\mathbf{-9}}}\textbf{ mol/L}}$}

6 0
3 years ago
23 grams of sodium reacts with 293 cm 3 of water that is initially at 298 k. it produces an enthalpy change of 197 kj. what is t
m_a_m_a [10]

448 K is the final temperature of the water.

<h3>What is specific heat capacity?</h3>

The specific heat capacity is defined as the quantity of heat (J) absorbed per unit mass (kg) of the material when its temperature increases by 1 K (or 1 °C), and its units are J/(kg K) or J/(kg °C).

Given,

the mass of Na is 23 g

The volume of water = 293 cm3

Mass of water = 293 g

Total solution mass = 23 g + 293 g = 316 g

Specific heat capacity of water = 4.18 J/Kg

The equation relating mass, heat, specific heat capacity and temperature change is:

q = mcΔT

197 kJ = 316 g x 4.18 J/Kg x (T_{finals} - T_ {initial})

197 kJ = 316 g x 4.18 J/Kg x ( T_{finals}-298 K)

0.1491429956 x 1000 =  T_{finals}-298 K

149.1429956 + 298 = T_{finals}

447.1429956 = T_{finals}

448 K = T_{finals}

Hence, 448 K is the final temperature of the water.

<h3>What does a high specific heat capacity mean?</h3>

A high specific heat capacity means that it can store a large amount of thermal energy for a small change in mass or temperature.

Learn more about specific heat capacity here:

brainly.com/question/2530523

#SPJ4

5 0
2 years ago
What is the independent variable of the penny lab
Sladkaya [172]
The independent variable in the experiment is the soap and the dependent variable in the experiment is the number of water drops on the surface of the penny. The control is the penny without soap.
6 0
3 years ago
Separating mixtures: filtration​
Ymorist [56]

hi these are the answers :)

5 0
2 years ago
What is the maximum number of moles of Al2O3 that can be produced by the reaction of .4 mol of Al with .4 mol of O2
Darya [45]

<u>Given:</u>

Moles of Al = 0.4

Moles of O2 = 0.4

<u>To determine:</u>

Moles of Al2O3 produced

<u>Explanation:</u>

4Al + 3O2 → 2Al2O3

Based on the reaction stoichiometry:

4 moles of Al produces 2 moles of Al2O3

Therefore, 0.4 moles of Al will produce:

0.4 moles Al * 2 moles Al2O3/4 moles Al = 0.2 moles Al2O3

Similarly;

3 moles O2 produces 2 moles Al2O3

0.4 moles of O2 will yield: 0.4 *2/3 = 0.267 moles

Thus Al will be the limiting reactant.

Ans: Maximum moles of Al2O3 = 0.2 moles

4 0
3 years ago
Read 2 more answers
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