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3 years ago

the magnitude of the electrical force acting between a +2.4x10-8c charge and 1+1.8x10-6 charge that are separated by 1.008m is

Physics

1 answer:

Temka [501]3 years ago

5 0

Answer:

3.83×10¯⁴ N

Explanation:

From the question given above, the following data were obtained:

Charge 1 (q₁) = +2.4x10¯⁸ C

Charge 2 (q₂) = +1.8x10¯⁶ C

Distance apart (r) = 1.008 m

Electrical constant (K) = 9×10⁹ Nm²/C²

Force (F) =?

The magnitude of the electrical force acting between the two charges can be obtained as follow:

F = Kq₁q₂ / r²

F = 9×10⁹ × 2.4x10¯⁸ × 1.8x10¯⁶ / (1.008)²

F = 0.0003888 / 1.016064

F = 3.83×10¯⁴ N

Thus the magnitude of the electrical force acting between the two charges is 3.83×10¯⁴ N

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3 years ago

The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula: =E−Ryn2 In this equation Ry stands for

skelet666 [1.2K]

Answer:

λ = 162 10⁻⁷ m

Explanation:

Bohr's model for the hydrogen atom gives energy by the equation

$E_{n}$ = - k²e² / 2m (1 / n²)

Where k is the Coulomb constant, e and m the charge and mass of the electron respectively and n is an integer

The Planck equation

E = h f

The speed of light is

c = λ f

E = h c /λ

For a transition between two states we have

$E_{n}$ - $E_{m}$ = - k²e² / 2m (1 / $n_{f}$ ² -1 / $n_{i}$ ²)

h c / λ = -k² e² / 2m (1 / $n_{f}$ ² - 1/ $n_{i}$ ²)

1 / λ = (- k² e² / 2m h c) (1 / $n_{f}$ ² - 1/ $n_{i}$ ²)

The Rydberg constant with a value of 1,097 107 m-1 is the result of the constant in parentheses

Let's calculate the emission of the transition

1 /λ = 1.097 10⁷ (1/10² - 1/8²)

1 / λ = 1.097 10⁷ (0.01 - 0.015625)

1 /λ = 0.006170625 10⁷

λ = 162 10⁻⁷ m

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3 years ago

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Answer:

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2 years ago

AYE I NEED HELP! Which two things balance and keep a main sequence star in equilibrium?

gladu [14]

Answer:

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Explanation:

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2 years ago

A planet of mass m moves around the Sun of mass M in an elliptical orbit. The maximum and minimum distance of the planet from th

zzz [600]

Answer:

the relation between the time period of the planet is

T = 2π √[( r1 + r2 )³ / 8GM ]

Explanation:

Given the data i the question;

mass of sun = M

minimum and maximum distance = r1 and r2 respectively

Now, using Kepler's third law,

" the square of period T of any planet is proportional to the cube of average distance "

T² ∝ R³

average distance a = ( r1 + r2 ) / 2

we know that

T² = 4π²a³ / GM

T² = 4π² [( ( r1 + r2 ) / 2 )³ / GM ]

T² = 4π² [( ( r1 + r2 )³ / 8 ) / GM ]

T² = 4π² [( r1 + r2 )³ / 8GM ]

T = √[ 4π² [( r1 + r2 )³ / 8GM ] ]

T = 2π √[( r1 + r2 )³ / 8GM ]

Therefore, the relation between the time period of the planet is

T = 2π √[( r1 + r2 )³ / 8GM ]

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3 years ago