Answer:
c. rate=−1/2Δ[HBr]/Δt=Δ[H2]/Δt=Δ[Br2]/Δt
Explanation:
Hello,
In this case, the undergoing chemical reaction is:
Thus, the rate is given as:
It is necessary to remember that each concentration to time interval is divided into the stoichiometric coefficient, that is why HBr has a 1/2. Moreover, the concentration HBr is negative since it is a reactant and it has a negative rate due to its consumption.
Therefore, the answer is:
c. rate=−1/2Δ[HBr]/Δt=Δ[H2]/Δt=Δ[Br2]/Δt
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Answer:
The correct answer is a. mixing a heat killed pathogenic strain of bacteria with a living non pathogenic strain can convert some of the living cells into the pathogenic form.
Explanation:
Griffith proved that DNA is the genetic material in some organism.To do this he described the process of transformation in which the heat killed pathogenic bacteria when mixed with a non pathogenic bacteria can convert the non pathogenic strain into pathogenic one. This principle is called transformation.
The transformation of non pathogenic strain into pathogenic one occur due to the uptake of DNA of the heat killed pathogenic bacteria by the non pathogenic strain.
Answer:
Covalent compounds are held by intermolecular forces while network solids are held by strong bonds in unit cells which are closely packed together.
Explanation:
Covalent compound molecules are held by vanderwaals forces which are relatively weak but strong enough to hold some covalent molecules together in the solid state. However, network solids contain atom to atom covalent bonds arranged in an orderly manner and regular repeating unit cells to form a rigid three dimensional network solid.
Answer:
BF 3
Explanation:
The geometry of the BF 3 molecule is called trigonal planar The fluorine atoms are positioned at the vertices of an equilateral triangle. The F-B-F angle is 120° and all four atoms lie in the same plane.
Colligative properties calculations are used for this type of problem. Calculations are as follows:
ΔT(boiling point) = 101.02 °C - 100.0 °C= 1.02 °C
<span>ΔT(boiling point) = (Kb)m
</span>m = 1.02 °C / 0.512 °C kg / mol
<span>m = 1.99 mol / kg
</span><span>ΔT(freezing point) = (Kf)m
</span>ΔT(freezing point) = 1.86 °C kg / mol (<span>1.99 mol / kg)
</span>ΔT(freezing point) = 3.70 <span>°C
</span>Tf - T = 3.70 <span>°C
T = -3.70 </span><span>°C</span>