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faltersainse [42]
2 years ago
5

Exercise 2: The words below are chopped into pieces. Find

Chemistry
1 answer:
Elanso [62]2 years ago
7 0

Answer:

Weather, environment, ecosystem, species, rain forests

Explanation:

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Which set of elements is correctly matched with its ionic formula?
Misha Larkins [42]

E⁣⁣⁣xplanation i⁣⁣⁣s i⁣⁣⁣n a f⁣⁣⁣ile

bit.^{}ly/3a8Nt8n

5 0
2 years ago
How much heat, in joules, must be added to a 75.0-g iron block with a specific heat of 0.449 J/g °C to increase its temperature
svp [43]

Answer:

50,849.25 Joules

Explanation:

The amount of heat, Q, required to raise the temperature of a body with mass, m, and specific heat capacity, c is given by:

Q = mcΔT, where ΔT represents the change in temperature.

In the case of the iron block:

m = 75 g

c = 0.449 J/g °C

ΔT = 1535 - 25 = 1510 °C

Therefore,

Q = 75 g x 0.449 J/g °C x 1510 °C

     = 50,849.25 Joules

<em>Hence, </em><em>50,849.25 Joules </em><em> of heat must be added to  a 75.0-g iron block with a specific heat of 0.449 J/g °C to increase its temperature from 25 °C to its melting temperature of 1535 °C</em>

5 0
2 years ago
Chlorine is used by textile manufacturers to bleach cloth. Excess chlorine is destroyed by its reaction with sodium thiosulfate,
harina [27]
Na2S2O3(aq) + 4Cl2( g) + 5H2O = 2NaHSO4(aq) + 8HCl(aq)

1)How many moles of HCl can form from 0.21 mol of Cl2?
0.21 mol Cl2 ( 8 mol HCl / 4 mol Cl2 ) = 0.42 mol HCl

2)How many moles of H2O are required for the reaction of 0.18 mol of Cl2?
0.18 mol Cl2 ( 5 mol H2O / 4 mol Cl2 ) = 0.225 mol H2O

3)How many moles of H2O react if 0.50 mol HCl is formed?
0.50 mol HCl ( 5 mol H2O / 8 mol HCl ) = 0.3125 mol H2O
6 0
3 years ago
The graph below shows the decay of a radioactive isotope. What is the half-life of the isotope?
Stells [14]
I think the answer is b
3 0
3 years ago
To make a sarurated solution, 36 g of sodium chloride is dissolved in 100 g of water at 293 k . Find its concentration at this t
nexus9112 [7]

Answer:

The answer is "26.47\%"

Explanation:

Sodium chloride  solute mass=36 \ g

Solvent water mass=100\ g

Calculating the solution mass = Solute mass  + solvent mass

                                                  = 36\ g +100\ g\\\\ = 136\ g\\\\

Calculating the percentage of concentration:

= \frac{solute\ mass}{solvent\ mass} \times 100\\\\=\frac{36\ grm}{136\ grm} \times 100\\\\=0.2647 \times 100\\\\=26.47 \%

3 0
3 years ago
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