Assuming the complete question is;
Consider the balanced equation below;
4NH3 + 3O2 = 2N2 +6H2O
What is the mole ratio of NH3 to N2;
From the balanced equation; the mole ratio of NH3 to N2 is 4:2.
The mole ratio is the ratio of moles of one substance to the number of moles of another substance in a balanced equation. In the above equation; 4 moles of ammonia requires 3 moles of oxygen to produce two moles of nitrogen and six moles of water.
[H+][OH-]=10-¹⁴
We are using this formula because we need to find the H+
substitute the value given for hydronium ion for OH-
[H+][4.19×10⁵]=10-¹⁴
[H+]=10-¹⁴÷4.19×10⁵
[H+]=2.387×10-¹⁹
Then the pH of the solution will be
pH= –log¹⁰ [H+]
pH = –log¹⁰ [2.387×10-¹⁹]
pH= –log¹⁰2.387+19log¹⁰
= –0.378+19
pH =18.622
Answer: The value of 
for this reaction is 250000.
Explanation:
The given equation is as follows.
... (1)
... (2)
To balance the atoms, multiply equation (2) by 3. Hence, the equation (2) can be re-written as follows.
... (3)
Now, subtract equation (1) from equation (3). So, the equation formed will be as follows.
This equation can also be re-written as follows.
This equation is similar to the equilibrium equation given to us.
Therefore, during this subtraction the equation constants get divided as follows.
Thus, we can conclude that the value of for this reaction is 250000.
Answer:
We need 113000 J of heat (option 2 is correct)
Explanation:
Step 1: Data given
Mass of liquid water = 50.0 grams
ΔHVap = 2260 J/g
Temperature = 100 °C
ΔHVap = The amount of heat released to change phase of a liquid water to steam = 2260 J/g
Step 2: Calculate the heat needed
Q =m* ΔHVap
⇒with Q = the amount of heat needed = TO BE DETERMINED
⇒with m = the mass of water = 50.0 grams
⇒with ΔHVap = 2260 J/g
Q = 50.0 grams * 2260 J
Q = 113000 J
We need 113000 J of heat (option 2 is correct)
Answer:
0.0272801
Explanation:
17.6 
* 
* 
= 0.02728005 in^2. You have to square the value of 2.54 to convert cm to cm^2.
