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stellarik [79]
3 years ago
13

(a) A small object with mass 3.75 kg moves counterclockwise with constant speed 1.55 rad/s in a circle of radius 2.55 m centered

at the origin. It starts at the point with position vector 2.55 i m. Then it undergoes an angular displacement of 8.95 rad.
(b) In what quadrant is the particle located and what angle does its position vector make with the positive x-axis?
(c) What is its velocity?
Physics
1 answer:
Eddi Din [679]3 years ago
8 0

Answer:3.95 m/s

Explanation:

Given

mass of object m=3.75 kg

\omega =1.55 rad/s

radius of circle =2.55 m

initial Position r=2.55 \hat{i}

angular displacement \theta _0=8.95 rad

8.95 radian can be written as

1.42 (2\pi )

i.e. Particle is at first quadrant with \theta =0.4242\pi \times \frac{180}{\pi }

\theta =76.36^{\circ}

(c)velocity is v=\omgea \times r

v=1.55\times 2.55=3.95 m/s

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I NEED HELP ASAP IM ON TIMER !!!!!!!!
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F

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3 0
2 years ago
A film of soapy water on top of a plastic cutting board has a thickness of 255 nm. What wavelength and color is most strongly re
Alona [7]

Answer:

the reflected wavelength is lano = 4.55 10⁻⁷ m which corresponds to the blue color

Explanation:

This is a case of reflection interference, we must be careful

* There is a 180º phase change when light passes from the air to the soap film (n = 1,339), but there is no phase change when passing from the pomp to the plastic (n = 1.3)

* the wavelength within the film is modulated by the refractive index

     λₙ =  λ₀ / n

if we consider these relationships the condition for constructive interference is

     2 t = (m + ½)  λₙ

     2t = (m + ½)  λ₀ / n

      λ₀ = 2t n / (m + ½)

we substitute the values

      λ₀= 2 255 10⁻⁹ 1,339 / (m + ½)

      λ₀  = 6.829 10⁻⁷ (m + ½)

let's calculate the wavelength for various interference orders

m = 0

       λ₀ = 6.829 10⁻⁷/ ( 0 +   ½ )

       λ₀ = 13.6 10⁻⁷

       it is not visible

m = 1

      λ₀ = 6,829 10⁻⁷/ (1 + ½)

       λ₀ = 4.55 10⁻⁷

      color blue

m = 2

      λ₀ = 6.829 10⁻⁷ / (2 + ½)

      λ₀ = 2,7 10⁻⁷

   it is not visible

therefore the reflected wavelength is lano = 4.55 10⁻⁷ m which corresponds to the blue color

5 0
3 years ago
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