Answer:
The correct answer is option b.
Explanation:

Mass of coal burned =
metric ton = 1.00\times 10^6\times 10^3 kg=10^9 kg[/tex]
1 metric ton = 
Molar mass of coal :

1 g = 0.001 kg
Moles of coal ,n :
If 2 moles of coal on combustion gives 270 moles of carbon dioxide than n moles of coal will give;
of carbon dioxide.
Molar mass of carbon dioxide gas = 44 g/mol = 0.044 kg/mol
Mass of
of carbon dioxide:

C. the square root of the mass of the particles.
<h3>Further explanation </h3>
Graham's law: the rate of effusion of a gas is inversely proportional to the square root of its molar masses or
the effusion rates of two gases = the square root of the inverse of their molar masses:

or

From this equation shows that the greater the mass of the gas, the smaller the effusion rate of the gas and vice versa, the smaller the mass of the gas, the greater the effusion velocity.
So if both gases are at the same temperature and pressure, the above formula can apply
In order to compute this, we must first take a couple of assumptions of:
1) The laboratory size so we can calculate its volume
2) The number of students working in the lab so we know the total gas produced
Let the lab be
11 m × 9 m × 6 m
The volume then computes to be:
594 m³
We know that
1 Liter is 1 dm³
1 m = 10 dm
1 m³ = 1000 dm³
Therefore, the room volume in liters is:
594,000 Liters
Let there be 30 students in the laboratory
Total gas being produced:
6 × 30
= 180 Liters
This works out to be:
0.03% of Hydrogen by volume
Therefore, there is no risk of explosion given our assumption of size and students.