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Nezavi [6.7K]
4 years ago
9

I bet half these people are kids from lhs rite now lol

Chemistry
2 answers:
Nana76 [90]4 years ago
7 0
I bet that half of them can type or write better than you can.
Sunny_sXe [5.5K]4 years ago
3 0
No not really this is a global thing millions use this
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Although coal is a complex mixture of substances, its elemental composition can be approximated by the formula <img src="https:/
Svetllana [295]

Answer:

The correct answer is option b.

Explanation:

2C_{135}H_{96}O_9NS+313O_2\rightarrow 270CO_2+2NO_2+2SO_2+96H_2O

Mass of coal burned = 1.00\times 10^6 metric ton = 1.00\times 10^6\times 10^3 kg=10^9 kg[/tex]

1 metric ton = 10^3kg

Molar mass of coal :

135\times 12g/mol+96\times 1g/mol+9\times 16 g/mol+1\times 14 g/mol+1\times 32 g/mol=1906 g/mol=1.906 kg/mol

1 g = 0.001 kg

Moles of coal ,n :\frac{10^9 kg}{1.906 kg/mol}=5.247\times 10^8 mol

If 2 moles of coal on combustion gives 270 moles of carbon dioxide than n moles of coal will give;

5.247\times 10^8 mol\times \frac{270}{2}=7.083\times 10^{10} mol of carbon dioxide.

Molar mass of carbon dioxide gas = 44 g/mol = 0.044 kg/mol

Mass of 7.083\times 10^{10} mol of carbon dioxide:

7.083\times 10^{10} mol\times 0.044 kg/mol=3.11\times 10^{11} kg

5 0
3 years ago
According to Graham’s law, the rate of effusion of a gas is inversely proportional to
VLD [36.1K]

C.  the square root of the mass of the particles.

<h3>Further explanation  </h3>

Graham's law: the rate of effusion of a gas is inversely proportional to the square root of its molar masses or  

the effusion rates of two gases = the square root of the inverse of their molar masses:  

\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }

or  

\rm M_1\times r_1^2=M_2\times r_2^2

From this equation shows that the greater the mass of the gas, the smaller the effusion rate of the gas and vice versa, the smaller the mass of the gas, the greater the effusion velocity.

So if both gases are at the same temperature and pressure, the above formula can apply

5 0
3 years ago
Hydrogen gas is explosive within the range of 4% - 75% v/v. Assuming that each student in your class produces 6 L of H2 and that
yan [13]
In order to compute this, we must first take a couple of assumptions of:
1) The laboratory size so we can calculate its volume
2) The number of students working in the lab so we know the total gas produced
Let the lab be
11 m × 9 m × 6 m
The volume then computes to be: 
594 m³
We know that 
1 Liter is 1 dm³
1 m = 10 dm
1 m³ = 1000 dm³
Therefore, the room volume in liters is:
594,000 Liters
Let there be 30 students in the laboratory
Total gas being produced:
6 × 30
= 180 Liters
This works out to be:
0.03% of Hydrogen by volume
Therefore, there is no risk of explosion given our assumption of size and students.
5 0
3 years ago
What is the name of the following Arrhenius acid, H3PO3?
pentagon [3]

Answer:

Phosphorous acid

Explanation:

8 0
3 years ago
Which state of matter is characterized by ionized particles, no definite shape or volume, and good electrical conductivity? gas
Sever21 [200]

Answer:

plasma

Explanation:

6 0
3 years ago
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