Answer:
The current through each lamp is 0.273 Amperes
Power dissipated in each lamp is 0.082W
Explanation:
Battery v = 1.5 V
Each lamp has resistance, r = 1.1 Ohms
The 5 lamps in series will therefore have total resistance, R = 5 * 1.1 = 5.5 Ohms
The current through each lamp, I = v/R = 1.5 / 5.5 = 0.273 Amperes
Power dissipated in each lamp = I² * r = 0.273² * 1.1 = 0.082W
Answer: Isentropic process is the process in fluids which have a constant entropy.
Explanation: The isentropic process is considered as the ideal thermodynamical process and has both adiabatic as well as reversible processes in internal form.This process supports no transfer of heat and no transformation of matter .The entropy of the provided mass also remains unchanged or consistent.These processes are usually carried out on material on the efficient device.
Answer:
The electrical power is 96.5 W/m^2
Explanation:
The energy balance is:
Ein-Eout=0
![qe+\alpha sGs+\alpha skyGsky-EEb(Ts)-qc=0](https://tex.z-dn.net/?f=qe%2B%5Calpha%20sGs%2B%5Calpha%20skyGsky-EEb%28Ts%29-qc%3D0)
if:
Gsky=oTsky^4
Eb=oTs^4
qc=h(Ts-Tα)
![\alpha s=\frac{\int\limits^\alpha _0 {\alpha l Gl} \, dl }{\int\limits^\alpha _0 {Gl} \, dl }](https://tex.z-dn.net/?f=%5Calpha%20s%3D%5Cfrac%7B%5Cint%5Climits%5E%5Calpha%20_0%20%7B%5Calpha%20l%20Gl%7D%20%5C%2C%20dl%20%7D%7B%5Cint%5Climits%5E%5Calpha%20_0%20%7BGl%7D%20%5C%2C%20dl%20%7D)
![\alpha s=\frac{\int\limits^\alpha _0 {\alpha lEl(l,5800 } \, dl }{\int\limits^\alpha _0 {El(l,5800)} \, dl }](https://tex.z-dn.net/?f=%5Calpha%20s%3D%5Cfrac%7B%5Cint%5Climits%5E%5Calpha%20_0%20%7B%5Calpha%20lEl%28l%2C5800%20%7D%20%5C%2C%20dl%20%7D%7B%5Cint%5Climits%5E%5Calpha%20_0%20%7BEl%28l%2C5800%29%7D%20%5C%2C%20dl%20%7D)
if Gl≈El(l,5800)
![\alpha s=(1-0.2)F(0-2)+(1-0.7)(1-F(0-2))](https://tex.z-dn.net/?f=%5Calpha%20s%3D%281-0.2%29F%280-2%29%2B%281-0.7%29%281-F%280-2%29%29)
lt= 2*5800=11600 um-K, at this value, F=0.941
![\alpha s=(0.8*0.941)+0.3(1-0.941)=0.77](https://tex.z-dn.net/?f=%5Calpha%20s%3D%280.8%2A0.941%29%2B0.3%281-0.941%29%3D0.77)
The hemispherical emissivity is equal to:
![E=(1-0.2)F(0-2)+(1-0.7)(1-F(0-2))](https://tex.z-dn.net/?f=E%3D%281-0.2%29F%280-2%29%2B%281-0.7%29%281-F%280-2%29%29)
lt=2*333=666 K, at this value, F=0
![E=0+(1-0.7)(1)=0.3](https://tex.z-dn.net/?f=E%3D0%2B%281-0.7%29%281%29%3D0.3)
The hemispherical absorptivity is equal to:
![qe=EoTs^{4}+h(Ts-T\alpha )-\alpha sGs-\alpha oTsky^{4}=(0.3*5.67x10^{-8}*333^{4})+10(60-20)-(0.77-600)-(0.3*5.67x10^{-8}*233^{4})=96.5 W/m^{2}](https://tex.z-dn.net/?f=qe%3DEoTs%5E%7B4%7D%2Bh%28Ts-T%5Calpha%20%20%29-%5Calpha%20sGs-%5Calpha%20oTsky%5E%7B4%7D%3D%280.3%2A5.67x10%5E%7B-8%7D%2A333%5E%7B4%7D%29%2B10%2860-20%29-%280.77-600%29-%280.3%2A5.67x10%5E%7B-8%7D%2A233%5E%7B4%7D%29%3D96.5%20W%2Fm%5E%7B2%7D)
Answer:
It is best to soak the new lifters in engine oil overnight in order to build a car engine from scratch, regardless of its length. Ensure all rings of the pistons are installed correctly. You should flip the block over and carefully install the top half of the main rod and bearing parts. Get the block out of your way and flip it over again. By flipping over the block, you’ll see the full effect. Ensure that the lifters are installed correctly.
Explanation: