Ask question

Ask question

All categories

3 years ago

14

2.14 (a) Using series/parallel resistance reductions, find the equivalent resistance between terminals A and B in the circuit of

Figure P2.14. (b) Repeat, but with C and D shorted together.

1 answer:

olasank [31]3 years ago

5 0

Answer:

There is no attachment

You might be interested in

A cylindrical drill with radius 4 is used to bore a hole through the center of a sphere of radius 5. Find the volume of the ring

ANTONII [103]

Answer:

The volume of the ring shaped solid that remains is 21 unit^3.

Explanation:

The total volume of the sphere is given as:

Volume of Sphere = (4/3)πr^3

where, r = radius of sphere

Volume of Sphere = (4/3)(π)(5)^3

Volume of Sphere = 523.6 unit^3

Now, we find the volume of sphere removed by the drill:

Volume removed = (Cross-sectional Area of drill)(Diameter of Sphere)

Volume removed = (πr²)(D)

where, r = radius of drill = 4

D = diameter of sphere = 2*5 = 10

Therefore,

Volume removed = (π)(4)²(10)

Volume removed = 502.6 unit^3

Therefore, the volume of ring shaped solid that remains will be the difference between the total volume of sphere, and the volume removed.

Volume of Ring = Volume of Sphere - Volume removed

Volume of Ring = 523.6 - 502.6

<u>Volume of Ring = 21 unit^3</u>

5 0

3 years ago

Which of the following statements is not necessarily true for a well-arranged floor plan?

lorasvet [3.4K]

A well arranged floor plan is one that optimises the given floor area. Floor plans are useful to help design furniture layout, wiring systems, and much more. Option B is the answer, since it does not meet the standard of a plan

<h3>What is a Floor Plan?</h3>

A floor plan is a scaled diagram of a room or building viewed from above. The floor plan may depict an entire building, one floor of a building, or a single room. It may also include measurements, furniture, appliances, or anything else necessary to the purpose of the plan.

<h3>Other properties of a floor plan are:</h3>

Maximize the property
Utilize space effectively
Accessibility
Flexibility
Functionality
Maximize the use of light
Attention to size
Fitting to your lifestyle

Learn more:

brainly.com/question/25057316

4 0

3 years ago

Don't break or crush mercury-containing lamps because mercury powder may be released.

alexandr402 [8]

A.

It would be released without a doubt so be careful!

Hope this helps :)

5 0

4 years ago

(a) The room-temperature electrical conductivity of a semiconductor specimen is 13 (Ω-m)-1. The hole concentration is known to b

Aleksandr-060686 [28]

Answer: a) 0.24E+20 m-3. b) p-type extrinsic.

Explanation:

The current density in a semiconductor is composed by two types of charge carriers: electrons and holes.

This parameter, is proportional to the Electric field within the semiconductor, being the proportionality constant, the electrical conductivity of the material, that takes into account the charge carrier concentrations, and the mobility for each type.

The expression for electrical conductivity is as follows:

σ = q . ne . µe + q . np . µp

Replacing by the given values, and the value of q (charge of an electron), we can get the only unknown that remains, ne , as follows:

ne =( σ – (q . np . µp)) / q µe = (13 (Ω.m)-1 – (1.6E-19) coul(4.0E+20) m-3.0.18) m2/V-s /( (1.6E-19).0.38) coul.m2/V-s

ne = 0.24E+20.

As ne is smaller than np, this means that the semiconductor behaves like a p-type extrinsic one.

7 0

3 years ago

One liter of oven-dry soil sampled from the Chorro Creek Ranch field requires 300 g of water to completely saturate it.

torisob [31]

Answer:

porosity=23.07%

x=5.974*10^9cm^3

Explanation:

One liter of oven-dry soil sampled from the Chorro Creek Ranch field requires 300 g of water to completely saturate it.

Calculate (a) its porosity, n, and (b) the volume of water required to saturate the top 20 cm of 1 hectare of the field.

-Porosity of a soil sample can be calculated in five ways but i shall use the formula below

porosity= $\frac{volume of pore}{volume of total} *100%$ %

volume pore volume of sample is equal to water volume used to saturate the soil

total volume=sample volume +pore volume

1L=1000cm^3

density of water=density=mass/volume

1g/cm^3=300g/volume

vol=300cm^3

total volume=300+1000

1300

porosity =(300/1300)*100%

porosity=23.07%

2. Recall that volume=area *height

1 hectare=1*10^9cm^2

the volume of soil sample=1*10^9cm^2*20cm

2*10^10cm^3

$porosity=\frac{x}{x+2*10^{10} } *100%$ %

23%=x/(x+2*10^10)*100%

x=5.974*10^9cm^3

8 0

3 years ago