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vivado [14]
2 years ago
14

2.14 (a) Using series/parallel resistance reductions, find the equivalent resistance between terminals A and B in the circuit of

Figure P2.14. (b) Repeat, but with C and D shorted together.
Engineering
1 answer:
olasank [31]2 years ago
5 0

Answer:

There is no attachment

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Give five general principles involved in the process of sewage filtration?​
aleksandr82 [10.1K]

Answer:

Some general principles are given below in the explanation segment.

Explanation:

Sewage treatment seems to be a method to extract pollutants from untreated sewage, consisting primarily of domestic sewage including some solid wastes.

<u>The principles are given below:</u>

  • Unless the components throughout the flow stream become greater than the ports or even the gaps throughout the filter layer, those holes would be filled as either a result of economic detection.
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  • Broadcast interception or interference.  
  • Inertial influence.
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8 0
3 years ago
¿Qué es la masonería?​
timofeeve [1]

Answer: freemasonry is Being a Mason is about a father helping his son make better decisions; a business leader striving to bring morality to the workplace; a thoughtful man learning to work through tough issues in his life.

Explanation:

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True or false? the arc welding power voltage used for GMAW and FCAW produces a constant voltage​
7nadin3 [17]

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2 years ago
In a Rankine cycle, superheated steam that enters the turbine at 1273.15 K and 1.8 MPa is then expanded to a vapor at 0.1 MPa. W
GrogVix [38]

Answer:

The shaft work generated per kilogram is -1.3 \frac{MJ}{kg}

Explanation:

Given:

Temperature T = 1273.15 K

Initial Pressure P_{1} = 1.8 MPa

Final pressure P_{2} = 0.1 MPa

From the table superheated,

h_{i} = 4635 \frac{K J}{Kg} and  h_{f} = 2706.54 \frac{K J}{Kg}

Work done by shaft is,

 W = h_{f} - h_{i}

 W = 2706.54 - 4635

 W = -1928.46 \frac{kJ}{kg}

But here efficiency is 0.56,

So work generated per kg is,

Work = 0.56 \times(- 1928.46)

Work = -1.3 \frac{MJ}{kg}

Therefore, the shaft work generated per kilogram is -1.3 \frac{MJ}{kg}

6 0
3 years ago
Velocity boundary layer thickness over a intermal fixed horizontal flat plate is the________ distance required for the fluid vel
antoniya [11.8K]

Answer:

Velocity boundary layer thickness over an internal or internal fixed flat plate is  normal to surface distance  required for the fluid velocity to attain the 99% of the free stream velocity value.

Explanation:

The affirmation is the current definition of velocity boundary layer thickness.

4 0
2 years ago
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