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Pie
3 years ago
12

An air conditioner using refrigerant R-134a as the working fluid and operating on the ideal vapor-compression refrigeration cycl

e is to maintain a space at 22°C while operating its condenser at 1000 kPa.
a. Determine the COP of the system when a temperature difference of 2°C is allowed for the transfer of heat in the evaporator.
Engineering
1 answer:
Oduvanchick [21]3 years ago
6 0

Answer:

COP=13.37

Explanation:

Considering the allowed temperature difference the temperature in the evaporator will be 20°. The enthalpy and entropy at this temperature are obtained from table for the saturated vapor phase:

h_1=261.64 kJ/kg

s_1=0.92254 kJ/kgK

The enthalpy at state 2 is determined from the given condenser pressure and the condition s_2 = s_1 with data from table using interpolation:  

h_2=273.18 kJ/kg

The enthalpy at states 3 and 4 is determined from the saturated liquid value for the condenser pressure from table:  

h_3=h_4=107.34 kJ/kg

the COP is then:

COP=qL/w

       = h_1- h_4/ h_2- h_1

       =13.37

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Answer:

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Given:

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Solution:

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Hence,                E = < 0.75*48 , 96 , 36*0.75> = < 36 , 96 , 27 > in

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                           unit(AD) = (1/12*sqrt(26)) * < 48 , -12 , 36 >

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Next:

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                            M_AD = 1359.17 lb-in

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Answer:

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Answer:

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Answer:

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typedef struct InventoryTag_struct {

int itemID;

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return 0;

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Explanation:

7 0
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