57.5 m/s
I did 2.3/0.04
I’m not sure if it’s correct though
Answer:
363 pounds 32 degrees
Explanation:
Express your answers numerically in pounds and degrees to three significant figures separated by a comma. slader
Answer:
Diode equation for reverse saturation current
Voltage at which diode goes into Resistive region:V=-5 volts
Voltage at which high level injection occurs:Va=0.55 volt
Voltage at which avalanche multiplication occurs:V=5volts
Explanation:
we take here forward and reverse 0.7 volt and -5 volt
As Diode current equation is express as
....................1
here
is total current through the diode and
is reverse saturated current and
is voltage drop across diode and
is idealized factor and
is thermal voltage
so here we know that when Bios is forward than
=
.................2
ans Bios is Reverse than
=
..................3
so here
1. diode reverse saturation current is express as
and
2. Voltage at which diode go into Reverse behavior will be
=
= -5 volt
and
3. voltage at which high level injection occur that is
Va = 0.55 volt
and
4. voltage at which avalanche multiplication occurs is
Va = 5 volt
Answer:
Explanation:
Cop of reversible refrigerator = TL / ( TH - TL)
TL = low temperature of freezer = 20 °F
TH = temperature of air around = 75 °F
Heat removal rate QL = 75 Btu/min
W actual, power input = 0.7 hp
conversion on F to kelvin = (T (°F) + 460 ) × 5 / 9
COP ( coefficient of performance) reversible = (20 + 460) × 5/9 / (5/9 ( ( 75 +460) - (20 + 460) ))
COP reversible = 480 / 55 = 8.73
irreversibility expression, I = W actual - W rev
COP r = QL / Wrev
W rev = QL / COP r where 75 Btu/min = 1.76856651 hp where W actual = 0.70 hp
a) W rev = 1.76856651 hp / 8.73 = 0.20258 hp is reversible power
I = W actual - W rev
b) I = 0.7 hp - 0.20258 hp = 0.4974 hp
c) the second-law efficiency of this freezer = W rev / W actual = 0.20258 hp / 0.7 hp = 0.2894 × 100 = 28.94 %
Answer:
engine
Explanation:
as long as the engine and evrything is running it should be good