Answer:
The answer to your question is:
Re (III) has 5 electrons
Sc(III) = has 1 electron
Ru(IV) = has 6 electrons
Hg(II) = has 10 electrons
Explanation:
75 Re(III) = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 6s² 4f¹⁴ 5d⁵
21 Sc(III) = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹
44 Ru(IV) = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d⁶
80 Hg(II) = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 6s² 4f¹⁴ 5d¹⁰
Is this multi answers or no?
In this item, it is assume that we are to express the dissociation of the formula unit given to be FeCl₂ into its ionic components.
As seen in the chemical formula, the unit is composed of iron (Fe) and chlorine (Cl). The dissociation is written as follows;
FeCl₂ --> Fe²⁺ + Cl⁻
This equation is balanced by multiplying the appropriate component with a number that would equate the number of atoms in both sides of the equation.
<em> FeCl₂ --> Fe²⁺ + 2Cl⁻</em>
Answer:
in my opinion find some stuff to help u with it test if you are aloud to bring in a revision boom into your test and get a good night sleep if you can and try not to get stressed about it
Helium would be the least I think