Answer:
P = 80.922 KW
Explanation:
Given data;
Length of load arm is 900 mm = 0.9 m
Spring balanced read 16 N
Applied weight is 500 N
Rotational speed is 1774 rpm
we know that power is given as
![P = T\times \omega](https://tex.z-dn.net/?f=%20P%20%3D%20T%5Ctimes%20%5Comega)
T Torque = (w -s) L = (500 - 16)0.9 = 435.6 Nm
angular speed
Therefore Power is
![P =\frac{435.6 \time 2 \pi \times 1774}{60} = 80922.65 watt](https://tex.z-dn.net/?f=P%20%3D%5Cfrac%7B435.6%20%5Ctime%202%20%5Cpi%20%5Ctimes%201774%7D%7B60%7D%20%3D%2080922.65%20%20watt)
P = 80.922 KW
Both the technicians are correct.
Explanation
Intake air temperature sensor is used in engines of vehicles to monitor the temperature of air entering the engine.
They are basically made of thermistors whose electrical resistance changes according to temperature.
Depending upon the reading and accuracy of intake air temperature sensor, the power-train control module (PCM) will decide about the air and fuel mixture ratio in the engine.
The hot air in engine requires less fuel to operate the engine parts while cold air requires more fuel to operate the engine.
The ratio of air and fuel mixture should be maintained in the engine and it is done by PCM only after getting the input from IAT. So technician B is saying correct.
Also the IAT works as a backup to support the engine coolant temperature sensor by the computer.
As the IAT checks the temperature of outside air, it will help to change the coolant temperature of the engine based on the environment.
Thus technician A is also correct. So both the technicians are correct.
C it would be c because that has more and the others have less
Answer:
The circulation around the cylinder is 0.163 ![\frac{m^{2} }{s}](https://tex.z-dn.net/?f=%5Cfrac%7Bm%5E%7B2%7D%20%7D%7Bs%7D)
Explanation:
Given :
Velocity of spinning cylinder
![\frac{m}{s}](https://tex.z-dn.net/?f=%5Cfrac%7Bm%7D%7Bs%7D)
Sea level density
![\frac{kg}{m^{3} }](https://tex.z-dn.net/?f=%5Cfrac%7Bkg%7D%7Bm%5E%7B3%7D%20%7D)
Sea level span
![\frac{N}{m}](https://tex.z-dn.net/?f=%5Cfrac%7BN%7D%7Bm%7D)
Lift per unit circulation is given by,
![L = \rho v c](https://tex.z-dn.net/?f=L%20%3D%20%5Crho%20v%20c)
Where
circulation around cylinder
![c = \frac{L}{\rho v}](https://tex.z-dn.net/?f=c%20%3D%20%5Cfrac%7BL%7D%7B%5Crho%20v%7D)
![c = \frac{6}{1.23 \times 30}](https://tex.z-dn.net/?f=c%20%3D%20%5Cfrac%7B6%7D%7B1.23%20%5Ctimes%2030%7D)
![\frac{m^{2} }{s}](https://tex.z-dn.net/?f=%5Cfrac%7Bm%5E%7B2%7D%20%7D%7Bs%7D)
Therefore, the circulation around the cylinder is 0.163 ![\frac{m^{2} }{s}](https://tex.z-dn.net/?f=%5Cfrac%7Bm%5E%7B2%7D%20%7D%7Bs%7D)
Answer:
D
Explanation:
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