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Answer:</h3>
Molecular equation:
2NH₄Br(aq) + Pb(C₂H₃O₂)₂(aq) →2NH₄C₂H₃O₂(aq) + PbBr₂(s)
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Explanation:</h3>
- The molecular equation of the reaction between aqueous ammonium bromide and aqueous lead (ii) acetate is given by;
2NH₄Br(aq) + Pb(C₂H₃O₂)₂(aq) →2NH₄C₂H₃O₂(aq) + PbBr₂(s)
- This is an example of a double displacement reaction where two ionic compounds exchange ions with each other to form two new compounds or salts.
- It can also be a precipitation reaction due to the formation of precipitate from two ionic compounds. Lead(ii) bromide is the precipitate formed during the reaction.
- The net ionic equation for the reaction is;
2Br⁻(aq) + Pb²⁺(aq)→ PbBr₂(s)
First, we need to calculate Ka in order to determine the pKa.
The formula for Ka = x^2/ initial concentration
initial concentration= 0.0147 M
we need to find x, and we can use the pH to find it because x is the [H+] concentration.
[H+]= 10^-pH----> [H+]= 10^-2.46= 0.00347
Ka= x^2/ initial---------> (0.00347)^2/ 0.0147= 8.18 x 10^-4
now that we have Ka, we can determine pKa using the following formula--> pKa= -log Ka
pKa= -log (8.18 x 10^-4)= 3.087
Need the answers to answer.
Answer:
yes they are minerals becomes they contain components that have things minerals contians.
Explanation: