About 1 gram. 1 part of 50 is 2%
2 <span>KOH +1 H3AsO4 →1 K2HAsO4 + 2 H2O</span>
Answer:
The correct answer is pOH= 11
Explanation:
From the aqueous acid-base equilibrium we know that
pH + pOH = 14
If we know pH, we can calculate pOH as follows:
pOH = 14 - pH
In this problem, the solution has a pH of 3, so:
pOH = 14 - 3 = 11
Answer: The molarity of the malonic acid solution is 0.08335 M
Explanation:

To calculate the molarity of acid, we use the equation given by neutralization reaction:

where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is NaOH.
We are given:

Putting values in above equation, we get:

Thus the molarity of the malonic acid solution is 0.08335 M