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nika2105 [10]
4 years ago
6

Help with this please !

Chemistry
2 answers:
ivann1987 [24]4 years ago
4 0
I feel like it’s 50 I’m not sure though
kotegsom [21]4 years ago
4 0
It wasn’t 50 n it was 200n
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If an object that stands 3 centimeters high is placed 12 centimeters in front of a plane mirror, how far from the mirror is the
ryzh [129]

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the mirror is 12 cm away from the image

Explanation:

; the image will be virtual and it will form at 12 cm distance behind the mirror.

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3 years ago
If you had excess chlorine, how many moles of aluminum chloride could be produced from 28.0 g of aluminum?
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Answer:

1.04 moles of AlCl₃

Explanation:

Balanced Equation:  2Al°(s) + 3Cl₂(g) => 2AlCl₃(s)

Approach => convert given data (28 g Al°) to moles. The number of moles  AlCl₃ would equal the number of moles aluminum because coefficients for Aluminum and Aluminum Chloride are equal.

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4 years ago
The particles that make up matter do not change during a ?
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Matter can only me transformed, but not created or destroyed.
8 0
4 years ago
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What halogen can react with sodium chloride solution to produce chlorine?
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5 0
3 years ago
Two identical containers, one red and one yellow, are inflated with different gases at the same volume and pressure. Both contai
Evgen [1.6K]

Answer:

8

Explanation:

Here we're dealing with the root mean square velocity of gases. We'll provide the formula in order to calculate the root mean square velocity of a gas:

v_{rms}=\sqrt{\frac{3RT}{M}}

Here:

R = 8.314 \frac{J}{K mol} is the ideal gas law constant;

T is the absolute temperature in K;

M is the molar mass of a compound in kg/mol.

We know that the gas from the red container is 4 times faster, as it takes 4 times as long for the yellow container to leak out, this means:

\frac{v_{rms, red}}{v_{rms, yellow}} = 4

We also know that the temperature of the red container is twice as large:

\frac{T_{red}}{T_{yellow}} = 2

Write the ratio of the velocities and substitute the variables:

\frac{v_{rms, red}}{v_{rms, yellow}}=\frac{\sqrt{\frac{3RT_{red}}{M_{red}}}}{\sqrt{\frac{3RT_{yellow}}{M_{yellow}}}}=4

Then:

\frac{\sqrt{\frac{3RT_{red}}{M_{red}}}}{\sqrt{\frac{3RT_{yellow}}{M_{yellow}}}}=\sqrt{\frac{3RT_{red}}{M_{red}}\cdot \frac{M_{yellow}}{3RT_{yellow}}}=\sqrt{\frac{T_{red}}{T_{yellow}}\cdot \frac{M_{yellow}}{M_{red}}}=4

From here:

16 = \frac{T_{red}}{T_{yellow}}\cdot \frac{M_{yellow}}{M_{red}}

Then:

\frac{M_{yellow}}{M_{red}} = \frac{16}{\frac{T_{red}}{T_{yellow}}} = \frac{16}{2} = 8

5 0
3 years ago
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