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3 years ago

Can the absolute energy states of the reactants (E) and products (E2) be measured in a chemical reaction?

1 answer:

8 0

When the products of a reaction have a lower enthalpy than the reactants: The reaction is endothermic. ... Can the absolute energy states of the reactants (E1) and products (E2) be measured in a chemical reaction?

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Using our understanding of the law of gravity. What happens to the gravity as we triple the distance between two objects?

MA_775_DIABLO [31]

Answer:

1/9

Explanation:

Newton’s Law of Universal Gravitation

Objects with mass feel an attractive force that is proportional to their masses and inversely proportional to the square of the distance.

F = GMm/r²

where

F - the gravitatioal force in Newtons,

M and m -two masses in kilograms

r - the separation in meters.

G - the gravitational constant (6.674*10 ⁻¹¹ N (m/kg) ² )

Because of the magnitude of G , gravitational force is very small unless large masses are involved.

So according to above equation , when the masses are not changing , force is inversely propotional to the square of distance

F1 ∝ 1/r² ---------------(1)

F2 ∝ 1(3r)²

F2 ∝ 1/9r²--------------(2)

(2)/(1)

$\frac{F_2}{F_1} =\frac{1}{9}\\ F_2 =\frac{F_1}{9}$

From their you get as the distance tripled, Force reduce by a factor of 9(3³)

for example , assume the distance get doubled ,Force reduce by a factor of 4 (2²)

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4 years ago

How was hubble important to our understanding of galaxies?

dusya [7]

Astronomer Hubble was the one that discovered that the universe has many galaxies and that the universe is expanding. That's why they name the Hubble Telescope under his name.

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4 years ago

The following questions consist of a statement and a reason .Answer these questions selecting the appropriate options given belo

Mamont248 [21]

Answer:

1)A)

1)A)2)A)

<h3>Hope it helps you ♡♡</h3>

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3 years ago

The inner and outer surfaces of a cell membrane carry a negative and positive charge, respectively. Because of these charges, a

BlackZzzverrR [31]

Answer:

E = 8.5 * 10^6 V/m

Explanation:

In general we have the following relation between the Electric Field and the Elecric Potential:

$\int\limits^2_1 {\vec{E} \cdot\vec{dl}} = V_{2} -V_{1}$

Due to the vector nature of the electric filed, we can only know the mean Electric field E across the membrane, and take it out from the integral, that is:

E = (ΔV)/L

Where L is the thickness of the membrane and ΔV is the potential difference.

Therefore:

E = 8.53933*10^6 V/m

rounding to the first tenth:

E = 8.5 * 10^6 V/m

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3 years ago

Two square air-filled parallel plates that are initially uncharged are separated by 1.2 mm, and each of them has an area of 190

julia-pushkina [17]

Answer:

$5.5\cdot 10^{-11} C$