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3 years ago

What is nacl monosaccharide disaccharide organic or inorganic?

1 answer:

8 0

<span>inorganic Let's look at the choices and see why they work, or don't work. monosaccharide * Otherwise known as a simple sugar. And NaCl is definitely not a sugar of any type. So this is wrong. disaccharide * Complex sugar. And NaCl doesn't qualify either. organic * A definition of an organic compound is one that has carbon in it. NaCl has sodium and chlorine. No carbon at all, so this isn't the right answer. And I wish that organic was an earlier choice, since the sugars mentioned above are organic compounds. inorganic * This is the only possible choice. Salt is not an organic compound since it doesn't have carbon. So it can't be a sugar either. But it can and is inorganic.</span>

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D. quantitative data can be recorded.

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3 years ago

What is the pH of a sample with [OH-] = 2.5 x 10-11 M?

sveticcg [70]

Answer:

The pH of the sample is 3,4.

Explanation:

We calculate the pOH from the formula pOH = -log (OH-). We know that for all aqueous solutions: pH + pOH = 14, and from there we clear pH:

pOH= -log (OH-)=10,60

pH + pOH = 14

pH + 10,60 = 14

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3 years ago

U-235 undergoes many different fission reactions. For one such reaction, when U-235 is struck with a neutron, Ce-144 and Sr-90 a

Lostsunrise [7]

Explanation:

A nuclear fission reaction is defined as the reaction in which a heavy nucleus splits into small nuclei along with release of energy.

The given reaction is $^{235}_{92}U + ^{1}_{0}n \rightarrow ^{144}_{58}Ce + ^{90}_{38}Sr + x^{1}_{0}n + y^{0}_{-1}\beta$

Now, we balance the mass on both reactant and product side as follows.

235 + 1 = $144 + 90 + (x \times 1) + (y \times 0)$

236 = 234 + x

x = 236 -234

= 2

So, now we balance the charge on both reactant and product side as follows.

92 + 0 = $58 + 38 + (x \times 0) + (y \times -1)$

92 = 96 - y

y = 4

Thus, we can conclude that there are 2 neutrons and 4 beta-particles are produced in the given reaction.

Therefore, reaction equation will be as follows.

$^{235}_{92}U + ^{1}_{0}n \rightarrow ^{144}_{58}Ce + ^{90}_{38}Sr + 2^{1}_{0}n + 4^{0}_{-1}\beta$

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3 years ago

PLS HELP NOW WILL GIVE BRAINLIEST

zvonat [6]

Answer:

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3 years ago

Can you help me with this?

sergey [27]

Look those up it will be easier

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3 years ago