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Feliz [49]
2 years ago
11

Pls halp. i give brainliest to 1st correct answer

Chemistry
1 answer:
Kruka [31]2 years ago
4 0

Answer:

C is correct

Explanation: Heat describes the transfer of thermal energy between molecules within a system and is measured in Joules. Heat measures how energy moves or flows. ... Temperature describes the average kinetic energy of molecules within a material or system and is measured in Celsius (°C), Kelvin(K), Fahrenheit (°F), or Rankine (R)

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Select all of the following statements that are false about ΔGo and ΔG:a) If the reaction has a large negative ΔGo value, the re
OLEGan [10]

Answer:

a) If the reaction has a large negative ΔGo value, the reaction must reach equilibrium at a small extent of reaction value

d) ΔGo and ΔG have the same magnitude, they just have opposite signs.

Explanation:

The fraction of the total heat energy if a system that does useful work is known as Gibb's free energy (G) and the change from the initial to final state is designated by \Delta G. It is observed that the values of \Delta G changes with experimental conditions such as temperature , pressure , concentration etc.

\Delta G^0 is the standard free energy change which is a balance of two natural tendencies of any system.

  1. Minimization of potential energy or enthalpic factor \Delta H^0

Maximization of disorderliness or entropic factor T\Delta S^0

Mathematically; \Delta G = \Delta H^0 - T\Delta S^0

Thus; from above mentioned, the statements that are true about ΔG⁰ and ΔG are:

ΔG⁰ and ΔG can have different values, they don't even have to have the same sign

For a reaction that reaches equilibrium, the minimum value of free energy must be at the equilibrium point

If ΔG⁰ , measured at an extent of reaction = 0.5, is positive, the sign for ΔG when the extent of reaction = 0.80 is also positive.

while the false statements include:

a) If the reaction has a large negative ΔG⁰ value, the reaction must reach equilibrium at a small extent of reaction value

d) ΔG⁰ and ΔG have the same magnitude, they just have opposite signs.

7 0
3 years ago
How does carbon exist in the atmosphere?
maks197457 [2]

Answer:

Carbon is found in the atmosphere mostly as carbon dioxide. Animal and plant respiration place carbon into the atmosphere. When you exhale, you are placing carbon dioxide into the atmosphere. Carbon is found in the lithosphere in the form of carbonate rocks. Carbonate rocks came from ancient marine plankton that sunk to the bottom of the ocean

Explanation:

hope this helps

6 0
3 years ago
True or False: The dots are placed as
rusak2 [61]

Answer:

Chemical Bond (False)

Explanation:

A mutual electrical attraction between the nuclei and valence electrons of different atoms that binds the atoms together

5 0
3 years ago
Read 2 more answers
A 25.00 ml sample of hydrochloric acid solution, hcl, is titrated with 0.0512 m naoh solution. the volume of naoh solution requi
Tresset [83]

A 25.00 ml sample of hydrochloric acid solution, HCl, is titrated with 0.0512 m NaOH solution. the volume of NaOH solution required is 21.68 ml  then the molarity of the HCl solution is 0.044 M .

Calculation ,

Formula used : M_{1} V_{1} =M_{2} V_{2}                            ...( i )

Where M is the molarity or concentration and V is the volume in ml .

concentration of hydrochloric acid solution ( M_{1}    ) = ?

concentration of NaOH ( M_{2} ) = 0.0512 M

volume of hydrochloric acid solution  ( V_{1} ) = 25.00 ml

volume of NaOH ( V_{2} ) =  21.68 ml

Putting the value of concentration , volume of both  in equation ( i ) we get .

M_{1}   × 25.00 ml = 0.0512 × 21.68 ml

M_{1}    = 0.0512 × 21.68 ml / 25.00 ml= 0.044 M

to learn more about hydrochloric acid solution please click here ,

brainly.com/question/24586675

#SPJ4

5 0
1 year ago
PLEASE HELP
Vinvika [58]

Answer:

11.6 grams of MgO can be produced with 4.63 grams of oxygen.

Explanation:

2Mg+O_2\rightarrow 2MgO

Mass of oxygen gas = 4.63 g

Moles of oxygen gas = \frac{4.63 g}{32 g/mol}=0.145 mol

According to reaction,  1 mole of oxygen gas gives 2 moles of magnesium oxide, then 0.1447 moles of oxygen gas will giv e:

\frac{2}{1}\times 0.145 mol=0.29 mol of magnesium oxide

Mass of 0.2894 moles of magnesium oxide:

= 0.29 mol × 40 g/mol = 11.6 g

11.6 grams of MgO can be produced with 4.63 grams of oxygen.

5 0
3 years ago
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