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Korvikt [17]
3 years ago
7

What is the density of a bar of silver with a mass of 68 g and a volume of 6.5 cm3?

Chemistry
1 answer:
Fudgin [204]3 years ago
3 0
The answer choice is B. <span>10.50 g/cm3</span>
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How does a balanced chemical equation demonstrate conservation of mass?
Mariulka [41]

Answer:

A balanced chemical equation will demonstrate the law of conservation of mass because the amount of elements on one side (reactants) will equal the amount of elements on the other side (products).

Explanation:

CH₄ + 4Cl₂ -> CCl₄ + 4HCl

Reactants:

1 C

4 H

8 Cl

Products:

1 C

4 H

8 Cl

6 0
2 years ago
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What can be said about a reaction with H = 62.4 kJ/mol and S = 0.145 kJ/(mol·K)?
Zigmanuir [339]
Answer:

At 430.34 K the reaction will be at equilibrium, at  T > 430.34 the reaction will be spontaneous, and at T < 430.4K the reaction will not occur spontaneously.

Explanation:

1) Variables:

G = Gibbs energy
H = enthalpy
S = entropy

2) Formula (definition)

G = H + TS

=> ΔG = ΔH - TΔS

3) conditions

ΔG < 0 => spontaneous reaction
ΔG = 0 => equilibrium
ΔG > 0 non espontaneous reaction

4) Assuming the data given correspond to ΔH and ΔS

ΔG = ΔH - T ΔS = 62.4 kJ/mol + T 0.145 kJ / mol * K

=>  T = [ΔH - ΔG] / ΔS

ΔG = 0 =>  T = [ 62.4 kJ/mol - 0 ] / 0.145 kJ/mol*K = 430.34K

This is, at 430.34 K the reaction will be at equilibrium, at  T > 430.34 the reaction will be spontaneous, and at T < 430.4K the reaction will not occur spontaneously.

3 0
3 years ago
Read 2 more answers
Hi May I know what is the answer and how to get it
Trava [24]

Answer:

D

Explanation:

When lead ions and sulfate ions bond, they form sediment so neither a nor b can be the answer.

The important thing is that two nitrate ions were originally bonded with one lead ion, while two potassium ions bonded with a sulfate ion.

Finally, since potassium and nitrate ions don't form sediment these two ions must remain. Therefore the answer is D

8 0
2 years ago
At what temperature<br> (Celsius) will water change from a<br> liquid to solid?
fiasKO [112]

Answer:

0 degrees Celsius

Explanation:

6 0
2 years ago
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A 25.0 g bold made of an alloy absorbed 250 J of heat as its temperature changed from 25.0 °C to 78.0 °C. What is the specific h
nata0808 [166]

Answer:

Specific heat of alloy = 0.2 j/ g.°C

Explanation:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Given data:

Mass of bold = 25 g

Heat absorbed = 250 J

Initial Temperature = 25°C

Final temperature = 78°C

Specific heat of alloy = ?

Solution:

Change in temperature:

ΔT = 78°C - 25°C

ΔT = 53°C

Now we will put the values in formula.

Q = m.c. ΔT

250 j = 25 g × c ×53°C

250 j = 1325 g.°C × c

250 j / 1325 g.°C = c

c = 0.2 j/ g.°C

8 0
3 years ago
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