A the first one represents an exponential growth chart
The empirical formula is K₂CO₃.
The empirical formula is the <em>simplest whole-number ratio of atoms</em> in a compound.
The ratio of atoms is the same as the ratio of moles, so our job is to calculate the <em>molar ratio of K:C:O</em>.
I like to summarize the calculations in a table.
<u>Element</u> <u>Moles</u> <u>Ratio</u>¹ <u>Integers</u>²
K 0.104 2.00 2
C 0.052 1.00 1
O 0.156 3.00 3
¹ To get the molar ratio, you divide each number of moles by the smallest number.
² Round off the number in the ratio to integers to integers (2, 1, and 3).
The empirical formula is K₂CO₃.
Carbon bonding is almost entirely COVALENT.
Carbon is an non metallic element with an atomic number of 6. The electronic configuration of carbon is 2,4. This configuration implies that carbon has four electrons in its outermost shell and it needs four more electron to attain the octet structure. Carbon normally strive to attain the octet structure by forming covalent bonds with other elements. Covalent bond is a type of chemical bond that involves sharing of electron pairs by the participating elements.
The solution that will have the lowest freezing point is 5.0 SODIUM CHLORIDE.
Adding solute to solvents usually result in the depression of the freezing point. The higher the quantity of the solute that is added, the lower the freezing point of the solution.
1) Balanced chemical reaction
2 KCl O3 ---> 2 KCl + 3 O2
2) stoichiometry
2 mol of KCl O3 / 3 mol O2
atomic and molecular masses
K: 39 g/mol
Cl: 35.5 g/mol
O: 16 g/mol
KClO3: 39 + 35.5 + 3*16 = 122.5 g/mol
O2: 2*16 = 32 g/mol
ratio of masses: 2* 122.5 g of K Cl O3 / 3* 32 g O2
4) final calculations
3.450 g KClO3 * 96 g O2 / 245 g KClO3 = 1.352 g O2
5) Answer: 1.352 gO2
