All categories

4 years ago

if a mixture of 90 g of hydrogen sulfide and 70.5 g of chromium oxide are allowed to raeact what mass of water can be formed

Chemistry

1 answer:

kow [346]4 years ago

3 0

Answer:

24.84 g

Explanation:

The balanced reaction equation is;

Cr2O3(s) + 3H2S(g) ⟶Cr2S3(s) + 3H2O(l)

We must first determine the limiting reactant

For chromium III oxide;

Amount of chromium III oxide = mass/molar mass = 70.5g/ 151.99 g/mol = 0.46 moles

If 1 mole of chromium III oxide yields 3 moles of water

0.46 moles of chromium III oxide yields 0.46 × 3 = 1.38 moles of water

For hydrogen sulphide

Amount of hydrogen sulphide = mass/molar mass = 90g/ 34 gmol-1 = 2.64 moles

If 3 moles of H2S yields 3 moles of water

2.64 moles of H2S yields 2.64 × 3/3 = 2.64 moles of water

Hence chromium III oxide is the limiting reactant.

Mass of water produced= 1.38 moles × 18gmol-1= 24.84 g

You might be interested in

study this chemical reaction: cr o2 -> cro2 then, write balanced half-reactions describing the oxidation and reduction that h

Klio2033 [76]

Answer:

Oxidation: Cr → Cr⁴⁺ + 4 e⁻

Reduction: 4 e⁻ + O₂ → 2 O²⁻

Explanation:

Let's consider the following redox reaction.

Cr + O₂ → CrO₂

Cr is oxidized. Its oxidation number increases from 0 to +4. The corresponding half-reaction is:

Cr → Cr⁴⁺ + 4 e⁻

O is reduced. Its oxidation number decreases from 0 to -2. The corresponding half-reaction is:

4 e⁻ + O₂ → 2 O²⁻

5 0

3 years ago

What is the name of this hydrocarbon?

grandymaker [24]

It's Butane (C4H10)

it's an alkane (CnH2n+2)

good luck

6 0

3 years ago

Read 2 more answers

3.0 x 108 m/s is the

Veseljchak [2.6K]

Answer:

Speed of light

Explanation:

The value 3.0 x 10⁸m/s is taken as the speed of light.

It is a constant.

It implies that light travels a distance of 3 x 10⁸ in just one second.
This value is for the speed of light in a vacuum when there are not particles obstructing its movement.
The speed of electromagnetic radiations in free space is also taken as the speed of light.

4 0

3 years ago

Which pair of atoms has the highest electronegativity difference? <br> ca, f, h, p, na

mamaluj [8]

I will state the electronegativities of each element.
Ca = 1.00
F = 3.98
H = 2.20
P = 2.19
Na = 0.93
The highest electronegative element is F (Fluorine).

6 0

3 years ago

50.g of NaNO3 was dissolved in 1250 mL of water. what is the molality of the solution? [ Molar mass of NaNO3 = 85 g/mol

Viefleur [7K]

Answer:

Approximately $0.47\; \rm mol \cdot L^{-1}$ (note that $1\; \rm M = 1 \; \rm mol \cdot L^{-1}$ .)

Explanation:

The molarity of a solution gives the number of moles of solute in each unit volume of the solution. In this $\rm NaNO_3$ solution in water,

Let $n$ be the number of moles of the solute in the whole solution. Let $V$ represent the volume of that solution. The formula for the molarity $c$ of that solution is:

$\displaystyle c = \frac{n}{V}$ .

In this question, the volume of the solution is known to be $1250\; \rm mL$ . That's $1.250\; \rm L$ in standard units. What needs to be found is $n$ , the number of moles of $\rm NaNO_3$ in that solution.

The molar mass (formula mass) of a compound gives the mass of each mole of units of this compound. For example, the molar mass of $\rm NaNO_3$ is $85\; \rm g \cdot mol^{-1}$ means that the mass of one mole of

$\displaystyle n = \frac{m}{M}$ .

For this question,

$\begin{aligned}&n\left(\mathrm{NaNO_3}\right) \\ &= \frac{m\left(\mathrm{NaNO_3}\right)}{M\left(\mathrm{NaNO_3}\right)}\\&= \frac{50\; \rm g}{85\; \rm g \cdot mol^{-1}} \\& \approx 0.588235\; \rm mol\end{aligned}$ .

Calculate the molarity of this solution:

$\begin{aligned}c &= \frac{n}{V} \\&= \frac{0.588235\; \rm mol}{1.250\; \rm L} \\&\approx 0.47\;\rm mol \cdot L^{-1}\end{aligned}$ .

Note that $1\; \rm mol \cdot L^{-1}$ (one mole per liter solution) is the same as $1\; \rm M$ .

8 0

3 years ago