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4 years ago

if a mixture of 90 g of hydrogen sulfide and 70.5 g of chromium oxide are allowed to raeact what mass of water can be formed

Chemistry

1 answer:

kow [346]4 years ago

3 0

Answer:

24.84 g

Explanation:

The balanced reaction equation is;

Cr2O3(s) + 3H2S(g) ⟶Cr2S3(s) + 3H2O(l)

We must first determine the limiting reactant

For chromium III oxide;

Amount of chromium III oxide = mass/molar mass = 70.5g/ 151.99 g/mol = 0.46 moles

If 1 mole of chromium III oxide yields 3 moles of water

0.46 moles of chromium III oxide yields 0.46 × 3 = 1.38 moles of water

For hydrogen sulphide

Amount of hydrogen sulphide = mass/molar mass = 90g/ 34 gmol-1 = 2.64 moles

If 3 moles of H2S yields 3 moles of water

2.64 moles of H2S yields 2.64 × 3/3 = 2.64 moles of water

Hence chromium III oxide is the limiting reactant.

Mass of water produced= 1.38 moles × 18gmol-1= 24.84 g

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In lab you have to prepare 530. 00 ml solution of 0. 125 m copper (ii) oxide. How many grams of solid sodium nitrate must be use

GarryVolchara [31]

The grams of solid copper oxide must be used to prepare a solution of 0.125m concentration is 5.26 g.

According to the definition of molar concentration of a substance dissolved in a solution is defined as the ratio of the number of moles to the volume of the solution.

C = n/V

The number of moles is equal to the given mass divided by the molar mass.

n = m/Mm = n ×m

Given,

The volume of the solution of copper oxide = 0.53

Molar mass of copper oxide = 79.5

Concentration of copper oxide = 0.125

CuO = cVM

= 0.125 × 0.53 × 79.5

= 5.26g

Thus, we concluded that the grams of solid copper oxide must be used to prepare a solution of 0.125m concentration is 5.26 g.

DISCLAIMER: The above question is wrong. The correct question is

Question: In lab you have to prepare 530. 00 ml solution of 0. 125 m copper (ii) oxide. How many grams of solid copper oxide must be used to prepare a solution of this concentration?

learn more about molar concentration :

brainly.com/question/14803618

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3 0

1 year ago

Why are the spheres representing nitrogen and oxygen different colors

Vlada [557]

Spheres representing Oxygen and Nitrogen are different colors so that it is easier for you to see.

5 0

3 years ago

Formula New Combination Predicted Formula

creativ13 [48]

Answer:

Formula New Combination Predicted Formula


NaCl potassium + chlorine KCl

AlCl₃ aluminum + fluorine AlF₃

CO₂ tin + oxygen SnO₂

MgCl₂ calcium + bromine CaBr₂

HCl cesium + iodine CsI

 CCl₄ silicon + bromine SiBr₄

Explanation:

1) The question is incomplete. The first part is missing.

This is the first part of the question.

Applying the principle that the elements of a particular column in the Periodic Table share the same chemical properties, complete the following chart. The first one has been done for you.


2) This is the given chart:

Formula New Combination Predicted Formula


Cu₂O silver + oxygen Ag₂O ← this is the example.

NaCl potassium + chlorine

 AlCl₃ aluminum + fluorine 

CO₂ tin + oxygen

 MgCl₂ calcium + bromine 

 HCl cesium + iodine 

 CCl₄ silicon + bromine 

3) This is how you find the new formula to complete the chart.

i) NaCl potassium + chlorine

Since potassium is in the same group of sodium, you predict that in the new formula Na is replaced by K giving KCl.

ii) AlCl₃ aluminum + fluorine

Since fluorine is in the same group that Al, then you predict that in the new formula Cl is replaced by F leading to AlF₃

iii) CO₂ tin + oxygen

Since tin is in the same group that C, you predict that in the new formula C is replaced by Sn leading to SnO₂

iv) MgCl₂ calcium + bromine

Since calcium is in the same group that Mg, and bromine is in the same group that Cl, you predict thea in the new formula calcium replaces Mg and bromine replaces Cl, leading to CaBr₂

v) HCl cesium + iodine

Since H is in the same column that cesium and Cl is in the same colum that iodine, you predict that in the new formula Cs replaces H and I replaces Cl leading to: CsI

 vi) CCl₄ silicon + bromine


Since silicon is in the same column that C and bromine is in the same column that Cl, you predict that in the new formula Si replaces C and Br replaces Cl, leading to SiBr₄

5 0

3 years ago

A test tube can be used to hold

Andrej [43]

What grade is this? I forgot but if u tell me the grade i can prob remember

5 0

3 years ago

Calculate the amount of heat needed to boil 120.g of acetic acid (HCH3CO2), beginning from a temperature of 16.7°C.

evablogger [386]

Answer:

The total amount of heat needed = 72.2116 kJ

Explanation:

Given that ;

the mass of acetic acid = 120.0 g

The initial temperature $T_1$ = 16.7 °C = (16.7 + 273.15 ) K = 298.85 K

The standard molar mass of acetic acid = 60.052 g/mol

Thus ; we can determine the number of moles of acetic acid;

number of moles of acetic acid = mass of acetic acid/ molar mass of acetic acid

number of moles of acetic acid = 120.0 g/ 60.052 g/mol

number of moles of acetic acid = 1.998 moles

For acetic acid:

The standard boiling point $T_2$ = 118.1 °C = ( 118.1 + 273.15 ) K = 391.25 K

The enthalpy of vaporization of acetic acid $\Delta H_{vap}$ = 23.7 kJ/mol

The heat capacity of acetic acid c = 2.043 J/g.K

The change in temperature Δ T = $T_2 - T_1$

Δ T = (391.25 - 289.85)K

Δ T = 101.4 K

The amount of heat needed to bring the liquid acetic acid at 16.7°C to its boiling point is ;

q = mcΔT

From our values above;

q = 120 g × 2.043 J/g.K × 101.4 K

q = 24859.2 J

q = 24859 /1000 kJ

q = 24.859 kJ

we have earlier calculated our number of moles o f acetic acid to be 1.998 moles;

Thus;

The needed amount of heat = $\Delta_{vap} *numbers \ of \ moles$

The needed amount of heat = $23.7 \ kJ/mol * 1.998 \ moles$

The needed amount of heat = 47.3526 kJ

Hence;

The total amount of heat needed = 24.859 kJ + 47.3526 kJ

The total amount of heat needed = 72.2116 kJ

4 0

3 years ago