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Mkey [24]
3 years ago
13

Magnesium reacts with hydrochloric acid, HCl, to form magnesium chloride and hydrogen gas. The reaction is: Mg + 2HCl → MgCl2 +

H2 What is the mass of HCl that would be required to completely react with 5.2 grams of Mg? 6.9 6.934 16 15.60
Chemistry
1 answer:
prisoha [69]3 years ago
5 0
Answer is: mass of HCl is 15,6 g.
Chemical reaction: Mg + 2HCl → MgCl₂ + H₂.
m(Mg) = 5,2 g.
n(Mg) = m(Mg) ÷ M(Mg).
n(Mg) = 5,2 g ÷ 24,3 g/mol.
n(Mg) = 0,213 mol.
From chemical reaction: n(Mg) : n(HCl) = 1 : 2.
n(HCl) = 0,426 mol.
m(HCl) = 0,426 mol · 36,45 g/mol.
m(HCl) = 15,6 g.
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explain why elements lying on the extreme right of the periodic table as from non metals but those lying on the extreme left a s
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Element at Extreme Left In Periodic Table:
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                                                     ns¹

where n is principle quantum number, which shows main energy level or shell. These metals can gain Noble gas configuration (stable configuration) either by loosing one electron or by gaining seven or more electrons. As it is quite reasonable to loose one electron instead of gaining seven or more electrons so these element easily loose one electron to gain noble as configuration. The Metallic character decreases along the period from left to right. So Group II-A (2) are second most metallic elements and so on. These metals at extreme left mainly exist in solid form.

Element at Extreme Right In Periodic Table:
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5 0
4 years ago
An electrochemical cell has the following standard cell notation: Al(s) | Al3+(aq) || Mg2+(aq) | Mg(s)
Soloha48 [4]

Answer:

a. Al(s) ⇄ Al⁺³(aq) + 3e⁻ (oxidation)

Mg²⁺(aq) + 2e⁻ ⇄ Mg(s) (reduction)

b. ΔE° = + 0.715 V

c.  It's an electrolytic cell, because it's a nonspontaneous reaction.

d. 2Al(s) + 3Mg²⁺(aq) ⇄ 2Al⁺³(aq) + 3Mg(s)

Explanation:

a. By the notation given, first is represented the oxidation reaction and then the reduction reaction, so they are:

Al(s) ⇄ Al⁺³(aq) + 3e⁻ (oxidation)

Mg²⁺(aq) + 2e⁻ ⇄ Mg(s) (reduction)

b. The standard potential of the cell (ΔE°) is the reduction potential of the oxidation less the reduction potential of the reduction. The reduction potentials are:

Al(s) = -1.66 V

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c. It's an electrolytic cell.

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d. 2Al(s) + 3Mg²⁺(aq) ⇄ 2Al⁺³(aq) + 3Mg(s)

The number of electrons must be the same, so the oxidation reaction is multiplied by 2, and the reduction reaction by 3.

5 0
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the answer is Te because O is oxygen.

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Genrish500 [490]

Answer:

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