Answer is: carbon dioxide and water <span>are released during cellular respiration.
</span>Chemical reaction of cellular respiration:
C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O.
There are 18 oxygen atoms (six in glucose and twelve in six molecules of oxygen) in left side of chemical reaction and also 18 oxygen atoms (twelve in six molecules of carbon dioxide and six in six molecules of water) at the right.
Given:
K = 0.71 = Kp
The reaction of sulphur with oxygen is
S(s) + O2(g) ---> SO2(g)
initial Pressure 6.90 0
Change -x +x
Equilibrium 6.90-x x
Kp = pSO2 / pO2 = 0.71 = x / (6.90-x)
4.899 - 0.71x = x
4.899 = 1.71x
x = 2.86 atm = pressure of SO2 formed
temperature = 950 C = 950 + 273.15 K = 1223.15 K
Volume = 50 L
Let us calculate moles of SO2 formed using ideal gas equation as
PV = nRT
R = gas constant = 0.0821 L atm / mol K
putting other values
n = PV / RT = 2.86 X 50 / 1223.15 X 0.0821 = 1.42 moles
Moles of Sulphur required = 1.42 moles
Mass of sulphur required or consumed = moles X atomic mass of sulphur
mass of S = 1.42 X 32 = 45.57 grams or 0.04557 Kg of sulphur
They meet all the environmental conditions an organism needs to survive
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Answer:
2K (s) + Cl₂ (g) ⇒ 2KCl (s)
Explanation:
Potassium and chlorine gas combine to form potassium chloride which is an ionic compound. The reaction is a type of combination reaction in which chlorine is being added to the metal, potassium.
Potassium reacts violently with the chlorine which is yellowish green in color to produce white solid of potassium chloride.
The balanced reaction is shown below as:
2K (s) + Cl₂ (g) ⇒ 2KCl (s)
