First a balanced reaction equation must be established:
![4Al _{(s)} + 3 O_{2} _{(g)}](https://tex.z-dn.net/?f=4Al%20_%7B%28s%29%7D%20%20%20%20%2B%20%20%203%20O_%7B2%7D%20%20_%7B%28g%29%7D)
→
![2 Al_{2} O_{3}](https://tex.z-dn.net/?f=2%20Al_%7B2%7D%20O_%7B3%7D%20)
Now if mass of aluminum = 145 g
the moles of aluminum = (MASS) ÷ (MOLAR MASS) = 145 g ÷ 30 g/mol
= 4.83 mols
Now the mole ratio of Al : O₂ based on the equation is 4 : 3
[
4Al +
3 O₂ → 2 Al₂O₃]
∴ if moles of Al = 4.83 moles
then moles of O₂ = (4.83 mol ÷ 4) × 3
=
3.63 mol (to 2 sig. fig.)
Thus it can be concluded that
3.63 moles of oxygen is needed to react completely with 145 g of aluminum.
Answer:
Nice and you
Explanation:
Please Mark me brainliest
A solid is hard and the molecules are packed together, a liquid can move around freely because the molecules aren't as packed together :)
Answer:
The atom must lose its three extra electrons to make the atom over all neutral.
Explanation:
The three subatomic particles construct an atom electron, proton and neutron. A neutral atom have equal number of proton and electron. In other words we can say that negative and positive charges are equal in magnitude and cancel the each other. For example if neutral atom has 6 protons than it must have 6 electrons.
If an atom have -3 charge it means three more electrons are added. In order to make the atom overall neutral three more electrons must be removed so that negative and positive charge becomes equal and cancel the effect of each other and make the atom neutral.
Electron:
The electron is subatomic particle that revolve around outside the nucleus and has negligible mass. It has a negative charge.
Symbol= e⁻
Mass= 9.10938356×10⁻³¹ Kg
It was discovered by j. j. Thomson in 1897 during the study of cathode ray properties.
Proton and neutron:
While neutron and proton are present inside the nucleus. Proton has positive charge while neutron is electrically neutral. Proton is discovered by Rutherford while neutron is discovered by James Chadwick in 1932.
Symbol of proton= P⁺
Symbol of neutron= n⁰
Mass of proton=1.672623×10⁻²⁷ Kg
Mass of neutron=1.674929×10⁻²⁷ Kg
Answer:
![V_{2} = 8.92 L](https://tex.z-dn.net/?f=V_%7B2%7D%20%3D%208.92%20L)
Explanation:
We have the equation for ideal gas expressed as:
PV=nRT
Being:
P = Pressure
V = Volume
n = molar number
R = Universal gas constant
T = Temperature
From the statement of the problem I infer that we are looking to change the volume and the pressure, maintaining the temperature, so I can calculate the right side of the equation with the data of the initial condition of the gas:
![P_{1} V_{1} =nRT](https://tex.z-dn.net/?f=P_%7B1%7D%20V_%7B1%7D%20%3DnRT)
![320Kpa*0.003m^{3} =nRT](https://tex.z-dn.net/?f=320Kpa%2A0.003m%5E%7B3%7D%20%3DnRT)
![1000L = 1m^{3}](https://tex.z-dn.net/?f=1000L%20%3D%201m%5E%7B3%7D)
So
![nRT= 0.96](https://tex.z-dn.net/?f=nRT%3D%200.96)
Now, as for the final condition:
![P_{2}V_{2}=nRT](https://tex.z-dn.net/?f=P_%7B2%7DV_%7B2%7D%3DnRT)
![P_{2} V_{2} =0.96](https://tex.z-dn.net/?f=P_%7B2%7D%20V_%7B2%7D%20%3D0.96)
clearing![V_{2}](https://tex.z-dn.net/?f=V_%7B2%7D)
![V_{2} =\frac{0.96}{P_{2} }](https://tex.z-dn.net/?f=V_%7B2%7D%20%3D%5Cfrac%7B0.96%7D%7BP_%7B2%7D%20%7D)
![V_{2} =0.00872m_{3}](https://tex.z-dn.net/?f=V_%7B2%7D%20%3D0.00872m_%7B3%7D)
![V_{2} = 8.92 L](https://tex.z-dn.net/?f=V_%7B2%7D%20%3D%208.92%20L)