Answer
I think it might be B
Explanation
Answer:
Explanation:
H2CO3 = H+ + HCO3- H2CO3 = 0.530 M Ka =4.4 X10^-7
Ka =[H+][A-]/[HA] [H+] = [A-]
0.530 M x 4.4 X10^-7= [H+}^2
2.32 X10^-7 = [H+}^2
23.2 X10^-8 = [H+}^2
4.83 X 10^-4 = [H+]
pH = - log 4.83 X 10^-4
pH = -(.68-4)
pH =-(-3.32)
pH= 3.32
Molar mass of LiBr (mm )= 86.845 g/mol
Molarity ( M ) = 4 M
Mass of solute ( m ) = 100 g
Volume ( V ) = in liters ?
V = m / mm * M
V = 100 / 86.845 * 4
V = 100 / 347.38
V = 0.2875 L
hope this helps!.
We can calculate the new volume of the gas using the Combined Gas Law:
(P1 x V1) / T1 = (P2 x V2) / T2
The initial volume, pressure, and temperature were 280 mL, 1.3 atm, and 291.15 K (changing the temperature into Kelvin is necessary), and the final volume, pressure, and temperature is V2, 3.0 atm, and 308.15 K. Plugging these values in and solving, we find that:
(P1 x V1) / T1 = (P2 x V2) / T2
(1.3 atm x 280 mL) / 291.15 K = (3.0 atm x V2) / 308.15 K
V2 = 128.42 mL
This makes sense considering the conditions, a small increase in temperature would make the gas expand but a significant increase in the pressure would cause the volume to decrease.
Hope this helps!
<u>Answer:</u> The mass of water produced in the reaction is 97.2 grams
<u>Explanation:</u>
We are given:
Moles of calcium hydroxide = 2.70 moles
The chemical equation for the reaction of calcium hydroxide and HCl follows:
By Stoichiometry of the reaction:
1 mole of calcium hydroxide produces 2 moles of water
So, 2.70 moles of calcium hydroxide will produce = 
of HCl
To calculate mass for given number of moles, we use the equation:
Molar mass of water = 18 g/mol
Moles of water = 5.40 moles
Putting values in above equation, we get:
Hence, the mass of water produced in the reaction is 97.2 grams
