Answer:
0.77 M
Explanation:
Molarity is the concentration of a solution per liter
C= concentration
n= number of moles
V= volume of solution
The formula we will use is C= n/V
C= n/V
C= (1.93 mol NaCl)/(2.5 L of solution)
C= 0.772 mol/L
Since this concentration is given in moles per liters of a solution, this concentration is also the molarity.
C= 0.772 mol/L
*Include two significant digits in final answer*
M= 0.77 M
Answer:
Molarity = moles ÷ liters
to get moles of NaBr divide grams of NaBr by its molar mass (mass of Na + mass of Bromine)
Na = 22.989769
Br = 79.904
molar mass of NaBr = 102.893769
6.6g ÷ 102.893769 = 0.064143826 moles of NaBr
0.064143826 moles ÷ 0.60 liters = 0.1069 molar concentration or 11 %
Missing question:<span> How many grams of oxygen are needed for complete combustion of the toluene?
Chemical reaction: </span>C₇H₈ + 9O₂ → 7CO₂ + 4H₂<span>O.
V(</span>C₇H₈) = 8,30 ml.
d(C₇H₈) = 0,867 g/ml.
n(C₇H₈) = V(C₇H₈) · d(C₇H₈).
m(C₇H₈) = 8,3 ml · 0,867 g/ml.
m(C₇H₈) = 7,19 g.
n(C₇H₈) = m(C₇H₈) ÷ M(C₇H₈).
n(C₇H₈) = 7,19 g ÷ 92,14 g/mol = 0,078 mol.
From chemical reaction: n(C₇H₈) : n(O₂) = 1 : 9.
n(O₂) = 9 · 0,078 mol = 0,702 mol.
m(O₂) = 0,702 mol · 32 g/mol = 22,5 g.
The answer to your question is Hubble’s law
The total mass is the sum of mass of KCl and mass of
water:
total mass = 38 g + 225 g
total mass = 263 g
Therefore the mass percent of KCl is:
% KCl = (38 g / 263 g) * 100%
<span>% KCl = 14.45%</span>
