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MaRussiya [10]
3 years ago
9

¿Por qué creen que la Ingeniería Metalúrgica es una carrera estratégica para el desarrollo de nuestro país?

Engineering
1 answer:
galina1969 [7]3 years ago
6 0

Answer:

La ingeniería metalúrgica implica el desarrollo de sistemas de producción industrial a través del desarrollo de distintas aleaciones de metales, mediante los cuales se generan componentes minerales específicos que hacen al desarrollo de nuevos metales de mayor calidad y eficacia en la producción industrial, la construcción, el desarrollo de maquinarias, etc.

Este tipo de ingeniería es una carrera estratégica para el desarrollo económico de las naciones, pues permite la creación de industrias mas eficientes, productos de mejor calidad y un mayor desarrollo del comercio a través de lo producido por las distintas fábricas del país, generando directa e indirectamente ingresos económicos para la nación.

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7 0
2 years ago
He is going ___ in the hot air ballon​
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2 years ago
Please define the coefficient of thermal expansion?
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7 0
3 years ago
One method that is used to grow nanowires (nanotubes with solid cores) is to initially deposit a small droplet of a liquid catal
7nadin3 [17]

Answer: maximum length of the nanowire is 510 nm

Explanation:

 

From the table of 'Thermo physical properties of selected nonmetallic solids at At T = 1500 K

Thermal conductivity of silicon carbide k = 30 W/m.K

Diameter of silicon carbide nanowire, D = 15 x 10⁻⁹ m  

lets consider the equation for the value of m

m = ( (hP/kAc)^1/2 )  = ( (4h/kD)^1/2 )  

m =  ( ((4 × 10⁵)/(30×15×10⁻⁹ ))^1/2 ) = 942809.04    

now lets find the value of h/mk    

h/mk = 10⁵ / ( 942809.04 × 30) =  0.00353

lets consider the value θ/θb by using the equation

θ/θb = (T - T∞) / (T - T∞)

θ/θb =  (3000 - 8000) / (2400 - 8000)

= 0.893

the temperature distribution at steady-state is expressed as;

θ/θb = [ cosh m(L - x) + ( h/mk) sinh m (L - x)]   / [cosh mL+  (h/mk) sinh mL]

θ/θb = [ cosh m(L - L) + ( h/mk) sinh m (L - L)]   / [cosh mL+  (h/mk) sinh mL]

θ/θb = [ 1 ]  / [cosh mL+  (h/mk) sinh mL]

so we substitute

0.893 =  [ 1 ]  / [cosh (942809.04 × L) +  (0.00353) sinh (942809.04 × L)]

L = 510 × 10⁻⁹m

L = 510 nm

therefore maximum length of the nanowire is 510 nm

4 0
3 years ago
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