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antiseptic1488 [7]
3 years ago
10

1. A copper block of volume 1 L is heat treated at 500ºC and now cooled in a 200-L oil bath initially at 20◦C. Assuming no heat

transfer with the surroundings, what is the final temperature?
Engineering
1 answer:
MaRussiya [10]3 years ago
7 0

Answer:

final temperature T = 24.84ºC

Explanation:

given data

copper volume = 1 L

temperature t1 = 500ºC

oil volume = 200 L

temperature t2 = 20ºC

solution

Density of copper \rho cu = 8940 Kg/m³

Density of light oil  \rho oil = 889 Kg/m³

Specific heat capacity of copper Cv = 0.384  KJ/Kg.K

Specific heat capacity of light oil Cv = 1.880 KJ/kg.K

so fist we get here mass of oil and copper that is

mass = density × volume   ................1

mass of copper = 8940 × 1 ×  10^{-3}  = 8.94 kg  

mass of oil = 889 × 200 × 10^{-3}  =  177.8 kg  

so we apply here now energy balance equation that is

M(cu)\times Cv \times (T-T1)_{cu} + M(oil) \times Cv\times (T-T2)_{oil}  = 0

put here value and we get T2

8.94\times 0.384 \times (T-500) + 177.8 \times 1.890\times (T-20)  = 0

solve it we get

T = 24.84ºC

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Answer:

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Explanation:

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u = 675.761\,\frac{kJ}{kg}

x = 0.123

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P = 476.16\,kPa

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\nu = 0.2066\,\frac{m^{3}}{kg}

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The mass stored in the vessel is:

m = \frac{V}{\nu}

m = \frac{10\times 10^{-3}\,m^{3}}{0.2066\,\frac{m^{3}}{kg} }

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Q_{in} = m\cdot (u_{2}-u_{1})

Q_{in} = (0.048\,kg)\cdot (1643.545\,\frac{kJ}{kg} - 675.761\,\frac{kJ}{kg} )

Q_{in} = 46.454\,kJ

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An engineer lives in Hawaii at a location where the annual rain fall is 300 inches. She decides to use the rain to generate elec
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Answer:

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Answer:

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<u />

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