Answer:
<em>1.228 x </em>
<em> mm </em>
<em></em>
Explanation:
diameter of aluminium bar D = 40 mm
diameter of hole d = 30 mm
compressive Load F = 180 kN = 180 x 
N
modulus of elasticity E = 85 GN/m^2 = 85 x 
Pa
length of bar L = 600 mm
length of hole = 100 mm
true length of bar = 600 - 100 = 500 mm
area of the bar A = 
= 
= 1256.8 mm^2
area of hole a = 
= 
= 549.85 mm^2
Total contraction of the bar = 
total contraction = 
==> 
= <em>1.228 x </em><em> mm </em>
Answer:
Explanation:
magnetic field due to circular wire
= μ₀ i / 2r
i is current and r is radius of coil .
Magnetic fields due to inner coil
μ₀ x 20 / (2 x 9.5 x 10⁻²)
Magnetic field due to outer coil
= μ₀ x I / (2 x 19 x 10⁻²) , I is the current to be calculated
Total field
μ₀ x 20 /( 2 x 9.5 x 10⁻²) +μ₀ x I / (2 x 19 x 10⁻²) = 0
20 + I /2 = 0
I = - 40 A
Current required is 40 A , and it will be in opposite direction.
1. I think it's the trails left by an electron as it moves around the nucleus.
2. The atomic number is the number of protons so it is 8.
3. It's mass is lowered but it is still the same element.
The distance decreases as the time increases
