Answer:
→
Explanation:
→
On the left you have:
Na: 1
Br: 2
On the right you have:
Na: 1
Br: 1
To get the Br to be the same on both sides, you would multiple the NaBr by 2. Then, you will have 2 Na so you put a coefficient of 2 in front of the Na aswell.
Answer:
2.13L
Explanation:
first you must find the amount(mols) of HCl in the solution. then you can use that to find the volume of the solution.
we know the:
mass m = 9.35g
molar mass M = 1 + 35.5=36.5 g/mol ( <em><u>check</u></em><em><u> </u></em><em><u>pe</u></em><em><u>riodic</u></em><em><u> </u></em><em><u>table</u></em><em><u> </u></em>)
concentration c = 0.120 mol/L
amount ( mols) of HCl:
n= m/M
n(HCl) = 9.35/36.5
= 0.2561644 mol
concentration of HCl in solution:
n= cV
V(HCl) = n/c
= 0.2561644/0.120
= 2.1347
= 2.13 L (<em>3sf</em><em>)</em><em> </em>
Answer:
The correct answer is 0.50 mol (NH₄)₃PO₄
Explanation:
The balanced chemical equation between liquid ammonia (NH₃) and H₃PO₄ is the following:
3 NH₃ + H₃PO₄ → (NH₄)₃PO₄
According to the equation, 3 mol of ammonia produce 1 mol of ammonium phosphate. Thus, the stoichiometric ratio is 1 mol (NH₄)₃PO₄/3 NH₃. To calculate the moles of (NH₄)₃PO₄, we multiply the ratio by 1.50 mol NH₃:
1.50 mol NH₃ x 1 mol (NH₄)₃PO₄/3 NH₃ = 0.50 mol (NH₄)₃PO₄