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krek1111 [17]
3 years ago
12

When 1.82 moles of HCL reacts with excess MnO2, how many moles of Cl2 form

Chemistry
2 answers:
s2008m [1.1K]3 years ago
5 0

The balanced reaction is:<span>

MnO2(s) + 4HCl(aq) → Cl2(g) + MnCl2(aq) + 2H2O(l)

We are given the amount of hydrochloric acid to be used for the reaction. This will be the starting point for the calculations.

1.82 mol HCl ( 1 mol Cl2 / 4 mol HCl) = 0.46 mol Cl2

<span>Therefore, 0.46 mol of chlorine gas is produced for the reaction of hydrochloric acid and manganese oxide.</span></span>

kakasveta [241]3 years ago
3 0

<u>Answer:</u> 0.455 moles of chlorine gas is formed.

<u>Explanation:</u>

We are given:

Moles of HCl = 1.82 moles

The chemical equation for the reaction of MnO_2 and HCl follows:

MnO_2(s)+4HCl(aq.)\rightarrow Cl_2(g)+MnCl_2(aq.)+2H_2O(l)

By Stoichiometry of the reaction:

If 4 moles of HCl produces 1 mole of chlorine gas

So, 1.82 moles of HCl will produce = \frac{1}{4}\times 1.82=0.455mol of chlorine gas

Hence, 0.455 moles of chlorine gas is formed.

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