Some physics kids were testing some changes they made to make their bikes go faster. Theyposted the following speeds on the clas
1 answer:
To do this, you need to make sure that all speeds are the same unit. Since there are three 2 speeds already in km/hr, it would be best that you match the other 2 speeds into that unit as well.
Conversion of 15,000m/hr:
time is already in hours so you just need to make convert the meters to kilometers.
Conversion of 4.3m/s
Now that they are all the same value, you can see that Fred at 4.3m/s was the fastest.
Conversion of 15,000m/hr:
time is already in hours so you just need to make convert the meters to kilometers.
Conversion of 4.3m/s
Now that they are all the same value, you can see that Fred at 4.3m/s was the fastest.
You might be interested in
Answer:
Diagrams in pictures
Explanation:
Using energy I can get
m g h = 1/2 m v^2
So the velocity at the end of the ramp is the squareroot of two times the initial height of the box times the gravity constant.
(H= 1,3m sin25)
V=2,32m/s
V= a t
And
X= v t +1/2 a t^2
Knowing v=2,32 m/s and x= 1,3 m
I can get
a= 6,21m/s2
F= m a
I can get the force of the box when it collides with the spring
F= 12, 425 N
The force the spring makes on the box then is
F = -12,425N = -k d
Then the spring's constant is k= 51,75N/m
To make the two diagrams I need the functions of time when the box slows down
I use the same two equations
V= a t
And
X= v t + 1/2 a t^2
Being now 2,32 my initial velocity and 0 my final velocity, and my distance 0,24 m.
I get there the time t=0,0689 seconds and the acceleration a= -33,67 m/s2 (negative because it's slowing down).
Then,
V(t)= - 33,67 m/s2 t for time between 0 and 0,689 sec
X(t)= 2,32 m/s t + 1/2 33,67 m/s2 t^2.
for time between 0 and 0,689 sec
Diagrams and equations are in the pictures
Answer:
B = 4.059 x 10¹⁵ T
Explanation:
Given,
Number of loop, N = 400
radius of loop, r = 0.65 x 10⁻¹⁵ m
Current, I = 1.05 x 10⁴ A
Magnetic field at the center of the loop
B = 4.059 x 10¹⁵ T