Answer:
196J
Explanation:
Given parameters:
Mass of skateboard = 1kg
Height off the ground = 20m
Unknown:
Potential energy = ?
Solution:
The potential energy is the energy due to the position of a body above the ground.
It is mathematically expressed as:
Potential energy = mass x acceleration due gravity x height
Potential energy = 1 x 9.8 x 20 = 196J
Answer:
Check attachment for better understanding
Explanation:
Given that
a= 0.75m
b=1.31m
c= 2.2m
Weight of pole is 26.90
Then, Fg = Weight = 26.90
Using Equilibrium of forces
ΣFy = 0
U — D — Fg = 0
U — D = Fg
U — D = 26.9
To calculate U,
We will take moment about point A.
ΣMa = 0
Let the clockwise moment be positive and anti-clockwise be negative
Fg(a+b) — U(a) = 0
26.9(1.31+0.75) —0.75U = 0
26.9(2.06) = 0.75U
0.75U = 55.414
U = 55.414/0.75
U = 73.89 N
To calculate D,
U — D = 26.9
73.89—D =26.9
73.89—26.9 = D
D = 46.99N
Explanation:
here, u = 5m/s,a = 3m/s2, v = 23m/s, t = ?, s = ?
v = u+at
23 = 5 + 3t
t = 23- 5/3 = 18/3 = 6 sec
s= ut + 1/2 at ^2
s = 5 * 6 + 1/2 * 3 * (6)^2
s = 30 + 1/2 * 3 * 36
s = 30 + 18 * 3
s= 30 + 54 = 84 m
here, u = 0, a = x, t = 5min = 300 sec, s= 5.8km = 5800m
s = ut + 1/2 at^2
5800 = 0 * 300 + 1/2 * x * (300)^2
5800 = 1/2 * x * 90000
5800= 45000 x
x = 5800/45000
x = 0.12m/sec^2
here, v = 0, t = 6sec, s = ?, a = - 9.8m/s2
s = UT + 1/2 at ^2
s = 29.4 * 3 + 1/2 * - 9.8 * (3)^2
s= 88.2 - 44.1
s= 44.1 m
s = ut + 1/2 at ^2
s = 0 * 1 + 1*2 * 9.8 * (1)^2
s = 4.9m
hope it helps you
I doubt that the physical properties will be affected, however, the chemical properties will be affected especially reaction rates
