As air pressure decreases, what happens

How does the work required to stretch a spring 2 cm compare with the work required to stretch it 1 cm

LuckyWell [14K]

Answer:

The work done required is $W_{1}=4W_{2}$

Explanation:

Given that,

Stretch spring = 2 cm

Stretch spring = 1 cm

We need to calculate the work done

Using formula of work done

$W_{1}=\dfrac{1}{2}kx_{1}^2$

Put the value into the formula

$W_{1}=\dfrac{1}{2}\timesk\times0.02^2$ .....(I)

We need to calculate the work done

Using formula of work done

$W_{2}=\dfrac{1}{2}kx_{2}^2$

Put the value into the formula

$W_{1}=\dfrac{1}{2}\timesk\times0.01^2$ .....(II)

We need to calculate the work done

Using equation (I) and (II)

$\dfrac{W_{1}}{W_{2}}=\dfrac{\dfrac{1}{2}\timesk\times0.02^2}{\dfrac{1}{2}\timesk\times0.01^2}$

$\dfrac{W_{1}}{W_{2}}=\dfrac{0.02^2}{0.01^2}$

$W_{1}=4W_{2}$

Hence, The work done required is $W_{1}=4W_{2}$

3 0

4 years ago

A person driving her car at 43 km/h approaches an intersection just as the traffic light turns yellow. She knows that the yellow

siniylev [52]

Answer:

If she hits the brakes, she will travel 13m before stopping. If she hits the gas, she will travel 28 before the light turns red. She should try to stop

Explanation:

To know how far she will travel before stopping, we need to use a kinematic formula which initial final velocity (Vf), initial velocity (V0), acceleration (a) and distance traveled(x):

$V_{f}^{2}=V_{0} ^{2} +2ax$

The moment in which she stops is when the final velocity equals zero. In this case, initial velocity is 43km/h=12m/s, and its maximum deceleration is -5.4m/s^2. Plugging in these values and solving for x:

$0^2=(12m/s)^2+2(-5.4m/s)x\\x=13m$

She will travel 13m before stopping

If she hits the gas, we need another kinematic formula, which relates distance traveled, initial speed, time (t) and acceleration.

$x=v_{0}t+0.5a*t^2$

If we know her car can accelerate from 43km/h=12m/s to 70km/h=19m/s in 8.1 s, we can know its acceleration:

$a=\frac{19m/s-12m/s}{8.1s}=0.86m/s^2$

In this case, the time before the light turns red is 2.0s. Plugging in all those values:

$x=12m/s*2s+0.5*0.86m/s^2*(2s)^2=28m$

If she hits the gas, she will travel 28m before the light turns red. She won't even reach the intersection, so she would try to stop.

5 0

3 years ago

. A force of 3.0 N acts through a distance of 12 m in

musickatia [10]

Answer:

<h3>The answer is 36 J</h3>

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 3 × 12

We have the final answer as

Hope this helps you

6 0

3 years ago

this is my 5th time waisting my points for this question because I could fail my final and I am not getting any answers so can s

Neko [114]

Answer:

<em>The person needs to apply 25 N to balance the seesaw</em>

Explanation:

<u>Moment</u>

The moment of a force is a measure of its tendency to cause a body to rotate about a specific point or axis.

The moment M of a force F located at a distance x from the axis of rotation is calculated as follows:

M = F.x

The image shows a moment of M=100 N.m is needed to be applied to balance the seesaw. It can also be noted that the distance to the pivot is x=4 m

To calculate the force needed to balance the seesaw, we solve for F:

$\displaystyle F=\frac{M}{x}$

$\displaystyle F=\frac{100\ N.m}{4\ m}$

F = 25 N

The person needs to apply 25 N to balance the seesaw

8 0

3 years ago

A kid on a playground swing makes 6 complete to-and-fro swings each 30 seconds

Evgesh-ka [11]

I assume that you want to find out what's the frequency is.

Number of oscillation = 6 which being done in 30 second.

which means the time period for 1 oscillation is 30 second/6 = 5 second

Frequency = 1/time period
= 1/5 Hertz

Hope this help

4 0

3 years ago