Answer:
Explanation:
Hello!!
Please remember that density=mass/volume.
In this case, we have the same mass for the feathers and the gold (1 pound).
So, if the mass is the same for both we have:
Df*Vg=Dg*Vf where f means feathers and g means gold.
In this case we see density is inversely related to volume. Both materials have the same mass. So which one have a bigger volume?
For this take a pound of feathers and submerge in a known volume of water. Note the displacement. Do the same for a pound of gold. Whichever has the smaller displacement, has the greater density.
In this case, Gold has the greatest density.
Answer:
1s^22s^22p^63s^23p^64s^23d^104p^4
Along each row of the periodic table, the atomic mass increases from left to right.
Explanation:
The elements in the periodic table are arranged based on rows and periods by increasing atomic number.
The periodic table has rows from left to right and columns from up and down. These rows are called periods and columns are called groups.
The electron organization in an atom explains about the shape and the elements in the same column have similar chemistry. The elements in each column have the same valence shell electron configuration and they have similar properties.
Answer:
Option D is correct = 58 g
Explanation:
Data Given:
mass of LiOH = 120 g
Mass of Li3N= ?
Solution:
To solve this problem we have to look at the reaction
Reaction:
Li₃N (s) + 3H₂0 (l) -----------► NH₃ (g) + 3LiOH (l)
1 mol 3 mol
Convert moles to mass
Molar mass of LiOH = 24 g/mol
Molar mass of Li₃N = 35 g/mol
So,
Li₃N (s) + 3H₂0 (l) -----------► NH₃ (g) + 3LiOH (l)
1 mol (35 g/mol) 3 mol (24 g/mol)
35 g 72 g
So if we look at the reaction 35 g of Li₃N react with water and produces 72 g of LiOH , then how many g of Li₃N will be react to Produce by 120 g of LiOH
For this apply unity formula
35 g of Li₃N ≅ 72 g of LiOH
X of Li₃N ≅ 120 g of LiOH
By Doing cross multiplication
Mass of Li₃N = 35 g x 120 g / 72 g
mass of Li₃N = 58 g
120 g of LiOH will produce from 58 g of Li₃N
So,
Option D is correct = 58 g
