Answer:
Cu + 4HNO3 ---> Cu(NO3)2 + 2NO2 + 2H2O.
Explanation:
Balancing:
Cu + 4HNO3 ---> Cu(NO3)2 + 2 NO2 + 2H2O.
Answer:
Electromagnetism studies the attraction of two bodies within a magnetic field.
Electromagnetic interaction is one of the four fundamental forces of the known universe. The charged particles interact electromagnetically through the exchange of photons. Experimentally it was concluded that the lines of force of magnetic fields were always closed, eliminating the possibility of a magnetic monopole, so that within a magnetic field there are two poles, in the solar system the attraction between earth and wind Solar is by means of a field.
The most correct theory on this topic is the Earth itself is protected from the solar wind by its magnetic field, most of those charged particles, and most of those charged particles are trapped in the Van Allen radiation belt.
Explanation:
The magnetosphere or magnetosphere is a region around a planet in which its magnetic field deflects most of the solar wind, forming a kind of protective shield against high energy charged particles from the Sun. This magnetic or magnetosphere atmosphere does not It is only in the solar system, but also usually occurs on other planets such as jupiter and others (since it occurs on all planets with a magnetic field)
Answer:
Hydration
Explanation:
In water, ions are surrounded by a sphere of water molecules called a hydration shell. The process of forming this shell is called hydration.
Answer:
The answer to your question is:
Vol of NO2 = 11.19 L
Vol of O2 = 2.8 L
Explanation:
Data
N2O5 = 56 g
STP T = 0°C = 273°K
P = 1 atm
MW N2O5 = 216 g
Gases law = PV = nRT
Process
216 g of N2O5 ---------------- 1 mol
54 g ----------------- x
x = (54 x 1) / 216
x = 0.25 mol of N2O5
2 mol of N2O5 ----------------- 4 mol of NO2
0.25 mol ------------------ x
x = (0.25 x 4) / 2 = 0.5 mol of NO2
V = nRT/P
V = (0.5)(0.082)(273) / 1 = 11.19 L
2 mol of N2O5 ----------------- 1 O2
0.25 N2O5 ---------------------- x
x = (0.25 x 1) / 2 = 0.125 mol
Vol = (0.125)((0.082)(273) / 1 = 2.8 L
Lithium
Li → Li⁺ + e⁻
Li 1s²2s¹ → Li⁺ 1s² + e⁻
