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MArishka [77]
3 years ago
8

An unknown compound a has the molecular formula c7h14o2. compound a absorbs strongly in the ir at 1700 cm-1. the 1h nmr spectral

data for compound a are given below. what is the structure of compound a?

Chemistry
2 answers:
scoundrel [369]3 years ago
7 0
The structure of compound A would be solid that is dense enough for antimicrobial form
slega [8]3 years ago
5 0

The structure of compound a is as shown in the figure a

<h3>Further explanation</h3>

A chemical compound is the chemical substance composed of many identical molecules and it composed of atoms from more than one element held together by chemical bonds. Ethyl isovalerate or C_7H_{14}O_2 is an organic compound that is the ester formed from ethyl alcohol and isovaleric acid. It has a fruity odor and flavor and useful for perfumery and food additive.

Nuclear magnetic resonance spectroscopy, most commonly known as NMR spectroscopy is the analytical chemistry technique for quality control and reserach to determine the content and purity of a sample as well as its molecular structure. NMR can quantitatively analyze mixtures containing known compounds.

An unknown compound a has the molecular formula C_7H_{14}O_2. Compound a absorbs strongly in the IR at 1700 cm^{-1}. the 1h NMR spectral data for compound a are given below. what is the structure of compound a?

The structure of compound a is as shown in the figure a, because the structure of compound a would be solid and dense enough for antimicrobial form

<h3>Learn more</h3>
  1. Learn more about compound brainly.com/question/1775854
  2. Learn more about molecular formula brainly.com/question/8316933
  3. Learn more about nmr brainly.com/question/10206242

<h3>Answer details</h3>

Grade: 9

Subject: chemistry

Chapter:   nmr

Keywords:  compound, molecular formula, c7h14o2, ir, nmr

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3 years ago
PbSO4 has a Ksp = 1.3 * 10-8 (mol/L)2.
Oduvanchick [21]

i. The dissolution of PbSO₄ in water entails its ionizing into its constituent ions:

\mathrm{PbSO_{4}}(aq) \rightleftharpoons \mathrm{Pb^{2+}}(aq)+\mathrm{SO_4^{2-}}(aq).

---

ii. Given the dissolution of some substance

xA{(s)} \rightleftharpoons yB{(aq)} + zC{(aq)},

the Ksp, or the solubility product constant, of the preceding equation takes the general form

K_{sp} = [B]^y [C]^z.

The concentrations of pure solids (like substance A) and liquids are excluded from the equilibrium expression.

So, given our dissociation equation in question i., our Ksp expression would be written as:

K_{sp} = \mathrm{[Pb^{2+}] [SO_4^{2-}]}.

---

iii. Presumably, what we're being asked for here is the <em>molar </em>solubility of PbSO4 (at the standard 25 °C, as Ksp is temperature dependent). We have all the information needed to calculate the molar solubility. Since the Ksp tells us the ratio of equilibrium concentrations of PbSO4 in solution, we can consider either [Pb2+] or [SO4^2-] as equivalent to our molar solubility (since the concentration of either ion is the extent to which solid PbSO4 will dissociate or dissolve in water).

We know that Ksp = [Pb2+][SO4^2-], and we are given the value of the Ksp of for PbSO4 as 1.3 × 10⁻⁸. Since the molar ratio between the two ions are the same, we can use an equivalent variable to represent both:

1.3 \times 10^{-8} = s \times s = s^2 \\s = \sqrt{1.3 \times 10^{-8}} = 1.14 \times 10^{-4} \text{ mol/L}.

So, the molar solubility of PbSO4 is 1.1 × 10⁻⁴ mol/L. The answer is given to two significant figures since the Ksp is given to two significant figures.

8 0
3 years ago
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