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MArishka [77]
3 years ago
8

An unknown compound a has the molecular formula c7h14o2. compound a absorbs strongly in the ir at 1700 cm-1. the 1h nmr spectral

data for compound a are given below. what is the structure of compound a?

Chemistry
2 answers:
scoundrel [369]3 years ago
7 0
The structure of compound A would be solid that is dense enough for antimicrobial form
slega [8]3 years ago
5 0

The structure of compound a is as shown in the figure a

<h3>Further explanation</h3>

A chemical compound is the chemical substance composed of many identical molecules and it composed of atoms from more than one element held together by chemical bonds. Ethyl isovalerate or C_7H_{14}O_2 is an organic compound that is the ester formed from ethyl alcohol and isovaleric acid. It has a fruity odor and flavor and useful for perfumery and food additive.

Nuclear magnetic resonance spectroscopy, most commonly known as NMR spectroscopy is the analytical chemistry technique for quality control and reserach to determine the content and purity of a sample as well as its molecular structure. NMR can quantitatively analyze mixtures containing known compounds.

An unknown compound a has the molecular formula C_7H_{14}O_2. Compound a absorbs strongly in the IR at 1700 cm^{-1}. the 1h NMR spectral data for compound a are given below. what is the structure of compound a?

The structure of compound a is as shown in the figure a, because the structure of compound a would be solid and dense enough for antimicrobial form

<h3>Learn more</h3>
  1. Learn more about compound brainly.com/question/1775854
  2. Learn more about molecular formula brainly.com/question/8316933
  3. Learn more about nmr brainly.com/question/10206242

<h3>Answer details</h3>

Grade: 9

Subject: chemistry

Chapter:   nmr

Keywords:  compound, molecular formula, c7h14o2, ir, nmr

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Predict the signs of !iH, !).S, and !).G of the system for the following processes at 1 atm: (a) ammonia melts at - 60°C, (b) am
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Answer:

Explanation:

(a) Given,

Normal melting point of ammonia is -77.7 °C

In this process , ammonia melts at - 60°C  

Now , during the process of melting , ammonia in the solid phase changes to liquid phase, and this increases the number of particles , therefore , the sign of entropy would be positive . And since , the process is an endothermic process , hence , the change in enthalphy sign will be positive .

Even , the temperature of the ammonia is more than its normal melting point .

Therefore ,  

TΔS > ΔH

Hence ,

ΔG < 0

Therefore ,  

ΔH = Positive

ΔS = Positive  

ΔG = Negative.

(b)Given,

Normal melting point of ammonia is -77.7 °C

In this process , ammonia melts at -77.7 °C

Now , during the process of melting , ammonia in the solid phase changes to liquid phase, and this increases the number of particles , therefore , the sign of entropy would be positive . And since , the process is neither endothermic process nor exothermic process, hence , the change in enthalphy sign will be neutral / zero .

Hence ,

ΔG < 0

Therefore ,  

ΔH = 0

ΔS = Positive ΔG = Negative.

(c) Given,

Normal melting point of ammonia is -77.7 °C

In this process , ammonia melts at - 100°C  

Now , during the process of melting , ammonia in the solid phase changes to liquid phase, and this increases the number of particles , therefore , the sign of entropy would be positive . And since , the process is an endothermic process , hence , the change in enthalphy sign will be positive .

Even , the temperature of the ammonia is less than its normal melting point .

Hence ,

ΔG > 0

Therefore ,  

ΔH = Positive

ΔS = Positive  

ΔG = Negative.

7 0
4 years ago
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