Approximate the real zeros of x^4-5x^3+6x^2-x-2 to the nearest tenth. a. 0.4, c. 4, 3.4 b. , 3.4 d. -4, 3.4
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Answer:
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Step-by-step explanation:
To find if a function intervals are possible, make sure the points are above the x axis.
The graph is getting positve around x=-3 but it isn't positive yet.
The graph is positve until x=-1
The graph becomes positive again again at x=2 and is positive infinitely forever.
So let set up our interval
We are going to start at -3 since that where it start getting positive, we then going to use the greater than sign since it get positve as we go to the right as of right now. We use the greater than becuase we are not going to include -3 as our solutions.
We then use a less than sign since the answer must be less than -1 becuase around-1 it start getting negative.
It becomes positive again at x=2 so since we going to left to right use the greater than sign becuase we are not including 2.
It infinitely becomes positive so our interval is x must be cause greater than w becuase it can be any interval greater than two.
and
The roots or zeroes are the x intercept of the graph,(when y=0, what is the x value.)
The x intercepts are -3 and 2.
The statement that correctly describes the horizontal asymptote of g(x) is:
Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.
<h3>What are the asymptotes of a function f(x)?</h3>- The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
- The horizontal asymptote is the limit of f(x) as x goes to infinity, as long as this value is different of infinity.
In this problem, the function is:
The horizontal asymptote is given as follows:
Hence the correct statement is:
Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.
More can be learned about asymptotes at brainly.com/question/16948935
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