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lilavasa [31]
3 years ago
7

Approximate the real zeros of x^4-5x^3+6x^2-x-2 to the nearest tenth. a. 0.4, c. 4, 3.4 b. , 3.4 d. -4, 3.4

Mathematics
2 answers:
garik1379 [7]3 years ago
8 0
Nsjsjskd922992939299292929191999292929292838383$$3’ejeieiixidid
levacccp [35]3 years ago
5 0

Answer:

x=−0.433107,3.352224

Rounding up should be -0.4 and 3.4

Step-by-step explanation:

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Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
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  • Left to Right  

Equality Properties

Multiplication Property of Equality

Division Property of Equality

Addition Property of Equality

Subtraction Property of Equality<u> </u>

<u>Algebra II</u>

Imaginary root <em>i</em>

  • <em>i</em> = √-1

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

5x² - 2 = -12

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. [Addition Property of Equality] Add 2 on both sides:                                    5x² = -10
  2. [Division Property of Equality] Divide 5 on both sides:                                 x² = -2
  3. [Equality Property] Square root both sides:                                                    x = ±√-2
  4. Rewrite:                                                                                                             x = ±√-1 · √2
  5. Simplify:                                                                                                             x = ±i√2
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Step-by-step explanation:

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