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lilavasa [31]
3 years ago
7

Approximate the real zeros of x^4-5x^3+6x^2-x-2 to the nearest tenth. a. 0.4, c. 4, 3.4 b. , 3.4 d. -4, 3.4

Mathematics
2 answers:
garik1379 [7]3 years ago
8 0
Nsjsjskd922992939299292929191999292929292838383$$3’ejeieiixidid
levacccp [35]3 years ago
5 0

Answer:

x=−0.433107,3.352224

Rounding up should be -0.4 and 3.4

Step-by-step explanation:

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Deffense [45]

Answer : The answer is option c evaporation

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3 years ago
Read 2 more answers
A book claims that more hockey players are born in January through March than in October through December. The following data sh
astra-53 [7]

Answer:

\chi^2 = \frac{(67-47.5)^2}{47.5}+\frac{(56-47.5)^2}{47.5}+\frac{(30-47.5)^2}{47.5}+\frac{(37-47.5)^2}{47.5}=18.295

Now we can calculate the degrees of freedom for the statistic given by:

df=(categories-1)=4-1=3

And we can calculate the p value given by:

p_v = P(\chi^2_{3} >18.295)=0.00038

Since the p value is very low we have enough evidence to reject the null hypothesis and we can conclude that the players' birthdates are not uniformly distributed throughout the​ year

Step-by-step explanation:

We need to conduct a chi square test in order to check the following hypothesis:

H0: There is no difference of birthdates distributed throughout the​ year

H1: There is a difference between birthdates distributed throughout the​ year

The level of significance assumed for this case is \alpha=0.05

The statistic to check the hypothesis is given by:

\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

The table given represent the observed values, we just need to calculate the expected values with the following formula E_i = \frac{total}{4}

And replacing we got:

E_{1} =\frac{67+56+30+37}{4}=47.5

And now we can calculate the statistic:

\chi^2 = \frac{(67-47.5)^2}{47.5}+\frac{(56-47.5)^2}{47.5}+\frac{(30-47.5)^2}{47.5}+\frac{(37-47.5)^2}{47.5}=18.295

Now we can calculate the degrees of freedom for the statistic given by:

df=(categories-1)=4-1=3

And we can calculate the p value given by:

p_v = P(\chi^2_{3} >18.295)=0.00038

Since the p value is very low we have enough evidence to reject the null hypothesis and we can conclude that the players' birthdates are not uniformly distributed throughout the​ year

3 0
4 years ago
I don't understand this question??​
Len [333]

Answer:

A

Step-by-step explanation:

3 0
3 years ago
Plz quick this is timed and I can’t do this
Alchen [17]

Answer:

68°

the brainlest answer I can get

7 0
3 years ago
I'm not good at mathematics and I need a bit of help.​
adell [148]

Answer:

2/3

Step-by-step explanation:

5/6*4/5=20/30

20/30 divided by ten equals 2/3

the answer is 2/3

5 0
3 years ago
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