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Zolol [24]
3 years ago
13

Please help me with physics ks3!! Sound waves and hearding (pic incl)

Physics
2 answers:
Nina [5.8K]3 years ago
7 0
Your answers for a), b), and c) are correct.  Good work !

d). The high noise levels in Technology and PE are more of
a concern to the teachers than to the students because the
students are only in there for 1 or 2 periods a day, but the
Technology and PE teachers are in there ALL day.

e).  Mr. Jones can't hear as high frequency as Jenny can because
he is much older than Jenny is.  Sadly, even without damage due to
loud noise, the ability to hear high frequencies does decrease with age.

f).  The wooden surfaces in the gym cause the gym to be louder
than it would be if it had carpet on the floor.  Carpet ... and soft
walls and ceilings ... absorb a lot of the sound that hits them. 
But hard surfaces don't absorb much of the sound that hits them,
so it just keeps bouncing around until it finally fades away. 

You can see this easily ... just go into the gym at your school, clap
your hands once, and notice how long you keep hearing the sound
after you clap. 
Archy [21]3 years ago
5 0
DB are units that might be good to add. 
They are louder as they use loud equipment or have practicals in which students talk.
It's more of a risk for teachers as they are exposed to it for every lesson they teach as students might only have one hour of it each day.
More likely reason is he's older so the level of pitch detection decreases with age.
f) the noise is reflected off the smooth surfaces and echoes
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________ can occur when an analog connection creates an electromagnetic field around its conductors, inducing its waveforms on a
KatRina [158]

Answer:

Crosstalk

Explanation:

The answer is Crosstalk as this phenomenon is most commonly associated with analog phone call.

Now, crosstalk is defined as a disturbance caused by the electric or magnetic fields of one telecommunication signal which affects a signal in an adjacent circuit. In a telephone circuit, crosstalk could result in hearing part of a voice conversation from another circuit. Hence, the phenomenon that causes crosstalk is called electromagnetic interference (EMI). This may occur in microcircuits within computers and audio equipments including within network circuits. This term is also usually applied to optical signals that interfere with each other.

6 0
3 years ago
I need help with this question how to solve it for Brass and Cooper
Ksenya-84 [330]

Take into account that density and relative density are given by:

\begin{gathered} \text{density}=\text{ mass/volume} \\ \text{relative density = density/density of water} \end{gathered}

Take into account that the volume associated to each of the given sustances in the table is determined by the Level Difference (because it is the change in the volume of the water of the recipient in which the substance is immersed).

The density of water in kg/m^3 is 1000 kg/m^3.

Due to the density must be given in kg/m^3, it is necessary to express the volumes of the table in m^3 and mass in kg, then, consider the following conversion factor:

1 m^3 = 1000000 ml

1 kg = 1000 g

Then, you obtain the following results:

Brass:

\begin{gathered} 53.2g\cdot\frac{1kg}{1000g}=0.0532kg \\ 6ml\cdot\frac{1m^3}{1000000ml}=0.000006m^3 \\ \text{density}=\frac{0.0532kg}{0.000006m^3}\approx8866.67\frac{kg}{m^3} \\ \text{relative density=}\frac{(\frac{8866.66kg}{m^3})}{(1000\frac{kg}{m^3})}\approx8.87 \end{gathered}

Cooper:

\begin{gathered} 57.4g=0.0574kg \\ 6ml=0.000006m^3 \\ \text{density}=\frac{0.0574kg}{0.000006m^3}\approx9566.67\frac{kg}{m^3} \\ \text{relative density=}\frac{\frac{9566.67kg}{m^3}}{1000kg}=9.57 \end{gathered}

3 0
1 year ago
A physics student swings a tennis ball connected to a rope in a vertical circle with a constant speed of 6.29 m/s. The ball has
Alex777 [14]

Answer:

r = 0.5 m

Explanation:

First we find the angular speed of the ball by using its period:

ω = θ/t

For the time period:

ω = angular speed = ?

θ = angular displacement = 2π rad

t = time period = 0.5 s

Therefore,

ω = 2π rad/0.5 s

ω = 12.56 rad/s

Now, for the radius:

v = rω

r = v/ω

where,

v = linear speed = 6.29 m/s

r = radius = ?

r = (6.29 m/s)/(12.56 rad/s)

<u>r = 0.5 m</u>

8 0
3 years ago
Hot coffee in a mug cools over time and the mug warms up. Which describes the energy in this system?
givi [52]
Thermal energy from the coffee is transferred to the mug.
3 0
4 years ago
If you apply an equal force to a larger mass, it will take longer to accelerate. <br> Tru or false
Makovka662 [10]

Answer:

true

Explication:

The acceleration of an object depends on the mass of the object, and the amount of force applied

5 0
3 years ago
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