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docker41 [41]
3 years ago
14

Machines can be made more efficient by reducing ___________________.

Physics
1 answer:
Aleks04 [339]3 years ago
3 0

Answer:

friction

wubba lubba dub dub

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is this true or false? an object with a mass of 9.0kg has an acceleration of 3m/s2. the force acting on it is 3N
ludmilkaskok [199]

The answer is "False". The force acting on the object is 27 N.

According to Newton's second law, when a force <em>F</em> acts on am object of mass <em>m</em>, it produces an acceleration <em>a</em>. The force is given by the expression,

F=ma

Thus, if the body has a mass of 9.0 kg and if it has an acceleration of 3 m/s², then, on substituting the values in the equation for force,

F=ma\\ =(9.0kg)(3m/s^2)\\ =27N

Thus, it can be seen that the force acting on the body is 27 N and not 3 N as is mentioned in the statement. Hence the statement is false.

5 0
3 years ago
A baseball pitcher throws a ball at 40 ms^-1. if the acceleration is approximately constant over a distance of 2 m, how large is
Reil [10]

We have the equation of motion v^2=u^2+2as, where v i the final velocity, u is the initial velocity, a is the acceleration and s is the displacement

Here final velocity, v = 40m/s

        Initial velocity, u = 0 m/s

        Displacement s = 2 m

Substituting 40^2=0^2+2*a*2\\ \\ a=400m/s^2

So the baseball pitcher accelerates at 400m/s^2 to release a ball at 40 m/s.

4 0
3 years ago
Two identical loudspeakers 2.00 m apart are emitting sound waves into a room where the speed of sound is 340 m/s. Abby is standi
Ganezh [65]

Answer:

242.85 Hz

Explanation:

For maximum intensity of sound, the path difference,ΔL = (n + 1/2)λ/2 where n = 0,1,2...

Since Abby is standing perpendicular to one speaker, the path length for the sound from the other speaker to him is L₁ = √(2.00² + 5.50²) = √(4.00 + 30.25) = √34.25 = 5.85 m.

The path difference to him is thus ΔL = 5.85 m - 5.50 m = 0.35 m.

Since ΔL = (n + 1/2)λ/2 and for lowest frequency n = 0,

ΔL = (n + 1/2)λ/2 = (0 + 1/2)λ/2 = λ/4

ΔL = λ = v/f and f = v/4ΔL where f = frequency of wave and v = velocity of sound wave = 340 m/s.

f = 340/(4 × 0.35) = 242.85 Hz

5 0
3 years ago
Azurite is a mineral that contains 55.1% of copper. How many meter of copper wire with diameter of 0.0113 in can be produced fro
soldier1979 [14.2K]

Answer:

1402.73 m

Explanation:

Mass of Azurite=3.25 lb

Percent of copper in AZurite mineral=55.1%

Diameter of  copper wire,d=0.0113  in

Radius of copper wire=r=\frac{d}{2}=\frac{0.0113}{2}=0.00565 in=\frac{565}{100000}=\frac{565}{100}\times \frac{1}{1000}=5.65\times 10^{-3}in

\frac{1}{1000}=10^{-3}

Density  of copper=\rho=8.96g/cm^3

1 lb=454 g

3.25 lb=3.25\times 454=1475.5 g

Mass of Azurite=1475.5 g

Mass of copper=\frac{55.1}{100}\times 1475.5=813 g

Density=\frac{Mass}{volume}

Using the formula

8.96=\frac{813}{volume\;of\;copper}

Volume of copper wire=\frac{813}{8.96}=90.7cm^3

Radius of copper wire=5.65\times 10^{-3}\times 2.54=14.35\times 10^{-3} cm

1 in=2.54 cm

Volume of copper wire=\pi r^2 h

\pi=3.14

Using the formula

90.7=3.14\times (14.35\times 10^{-3})^2\times h

h=\frac{90.7}{3.14\times (14.35\times 10^{-3})^2}

h=140273 cm

1 m=100 cm

h=\frac{140273}{100}=1402.73 m

Hence, the length of copper wire required=1402.73 m

7 0
3 years ago
In the illustration, which solute will dissolve first?
11Alexandr11 [23.1K]
A cause the sugar cubes are small enough to dissolve fast
6 0
4 years ago
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